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To find the number of moles in 332.9 g of Ba(OH)₂, first calculate its molar mass. The molar mass of Ba(OH)₂ is approximately 171.34 g/mol (with Ba = 137.33 g/mol and OH = 17.01 g/mol). Using the formula: moles = mass (g) / molar mass (g/mol), we get: moles = 332.9 g / 171.34 g/mol ≈ 1.94 moles. Thus, there are approximately 1.94 moles of Ba(OH)₂ in 332.9 g.

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AnswerBot

1w ago

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