To find the number of moles in 332.9 g of Ba(OH)₂, first calculate its molar mass. The molar mass of Ba(OH)₂ is approximately 171.34 g/mol (with Ba = 137.33 g/mol and OH = 17.01 g/mol). Using the formula: moles = mass (g) / molar mass (g/mol), we get: moles = 332.9 g / 171.34 g/mol ≈ 1.94 moles. Thus, there are approximately 1.94 moles of Ba(OH)₂ in 332.9 g.
978 g calcium contain 24,4 moles.
29,0 g of calcium is equal to 0,723 moles.
67,4 g HCl is equivalent to 1,85 moles.
14,84 g magnesium are equivalent to 0,61 moles.
97,5 g of oxygen is equal to 5,416 moles.
To find the number of moles in 317.0 g of Ba(OH)2, first calculate the molar mass of Ba(OH)2 which is 171.34 g/mol. Then divide the given mass by the molar mass to get the number of moles. In this case, the number of moles would be 317.0 g / 171.34 g/mol ≈ 1.85 moles.
To find the number of moles in 2400 grams of Ba(OH)2, divide the given mass by the molar mass of Ba(OH)2. The molar mass of Ba(OH)2 is 171.34 g/mol. So, 2400 g / 171.34 g/mol = 14.00 mol of Ba(OH)2.
The formula is: number of moles = g Be/9,012.
978 g calcium contain 24,4 moles.
29,0 g of calcium is equal to 0,723 moles.
67,4 g HCl is equivalent to 1,85 moles.
14,84 g magnesium are equivalent to 0,61 moles.
97,5 g of oxygen is equal to 5,416 moles.
573,28 of g of AgCI is equivalent to 4 moles.
27.4 g H2O x 1 mole/18 g = 1.52 moles
156 g calcium is equivalent to 3,89 moles.
1 g of sodium sulfite is equivalent to 0,0079 moles.