To do this, you need to know the molecular weight of the element you're dealing with, by adding up the atomic weights of the elements involved (found on any Periodic Table). The molecular weight is the mass in grams of the compound in one mole - this will provide you with a conversion factor. So take the measurement in grams and divide it by the molecular weight to convert to moles. Really what you're doing is multiplying the number by 1 mole, and dividing it by the equivalent of one mole, the molecular weight. That's the thought process behind unit analysis and how you get your "units to cancel".
In this case, the answer is about .4886 moles MgSO3.
0.25 mole of H2O
Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters) 5M C6H12O6 = moles C6H12O6/0.450 liters = 2.25 moles C6H12O6 (180.156 grams/1 mole C6H12O6) = 405.351 grams of glucose ( you do significant figures )
To find the mass of the sample, we can use the formula: Mass = number of moles x molar mass First, calculate the molar mass of cinnamaldehyde (C9H8O) which is 912 + 81 + 1*16 = 132 g/mol. Then, multiply the number of moles (0.0976) by the molar mass to get the mass of the sample, which is 0.0976 mol * 132 g/mol = 12.91 grams.
There are approximately 4.86 x 10^24 molecules in 81 mol of CO2. This can be calculated by multiplying Avogadro's number (6.022 x 10^23) by the number of moles (81).
81 grams is equal to 2.85719092
0.25 mole of H2O
Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters) 5M C6H12O6 = moles C6H12O6/0.450 liters = 2.25 moles C6H12O6 (180.156 grams/1 mole C6H12O6) = 405.351 grams of glucose ( you do significant figures )
The molar mass of aluminum is approximately 27.0 g/mol. To find the mass of 3.0 moles of aluminum, you can multiply the number of moles by the molar mass: 3.0 moles * 27.0 g/mol = 81.0 grams of aluminum.
There are 453.59237 grams in one pound. Therefore to get amount of pounds in grams, value in grams has to be divided by amount of grams in one pound: 81 grams = [grams] / 453.59237 = 81 / 453.59237 = 0.1786 pounds
81 grams is equivalent to approximately 0.18 pounds.
About 81 grams of fat
To find the mass of the sample, we can use the formula: Mass = number of moles x molar mass First, calculate the molar mass of cinnamaldehyde (C9H8O) which is 912 + 81 + 1*16 = 132 g/mol. Then, multiply the number of moles (0.0976) by the molar mass to get the mass of the sample, which is 0.0976 mol * 132 g/mol = 12.91 grams.
There are approximately 4.86 x 10^24 molecules in 81 mol of CO2. This can be calculated by multiplying Avogadro's number (6.022 x 10^23) by the number of moles (81).
81 calories. For each gram of fat you have nine calories. 9 times 9 is 81 - therefore 81 calories.
81 grams is equal to 2.85719092
0.18 lbs
324 teaspoons