How many grams are in 2.5 moles of sulfuric acid?

Answer 1

Using the Periodic Table first calculate the Relative Molecular Mass (Mr) of sulphuric acid.

The formula for sulphuric acid is H2SO4

Hence

H x 2 = 1 x 2 = 2

S x 1 = 32 x 1 = 32

O x 4 = 16 x 4 = 64

Add

2 + 32 64 = 87

Next remember the algebraic equ'n for calculating moles

Moles = mass(g / Mr

mol(H2SO4) = 1.5g / 98

mol(H2SO4) = 0.0153 moles.

Answer 2

The mol mass of sulfuric acid is 98.078 g/mol, 98 g of sulfuric acid therefore contains 0.9992 moles. Using consistent significant figures and your calculations, 98 g sulfuric acid would be equal to 1.0 mol sulfuric acid.

Answer 3

0.173 moles

The molar mass of H2SO4 is 98.1 grams per mole. To figure out how many moles there are in a given mass of something, divide the mass of the sample by the molar mass of the substance. So: 17.0g / 98.1g mol-1 = 0.173 mol

Answer 4

For this you need the atomic (molecular) mass of H2SO4. Take the number of grams and divide it by the Atomic Mass. Multiply by one mole for units to cancel. H2SO4= 98.1 grams

201 grams H2SO4 / (98.1 grams) = 2.05 moles H2SO4

Answer 5

For this you need the atomic (molecular) mass of H2SO4. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. H2SO4=98.1 grams

38.28 grams H2SO4 / (98.1 grams) = .390 moles H2SO4

Answer 6

2 mole sulfuric acid (98.086 grams/1 mole H2SO4)

= 196.172 grams

Answer 7

As the molar mass of sulfuric acid is 98 g/mol, there would be 245 g.

Answer 8

588 grams of sulfuric acid is equal to 6 moles.

Answer 9

This value is 9,2.10 ex.21 moles.

Answer 10

98. Grams