1 mole of dichromate releases 3 moles of atomic oxygen during oxidation process so it may oxidize 3 moles of butanol.
Added:
The answer (three moles butanon) is correct, but not the explanation.
This oxidation has nothing to do with 'oxygen atoms', instead CrVI (in bichromate) taking up 3 electrons to form CrIII cations.
Secundairy alcohols, like 2-butanol, are only oxidised till a keton is formed (butanon), according to:
3 (CH3)CHOH(C2H5) + Cr2O72- + 8 H+ --> 3 (CH3)CO(C2H5) + 2 Cr3+ + 7 H2O
Please note there is NO change in the number of 'oxygen atoms' in the 2-butanol changing to butanon.
To find the number of moles in (3.52 \times 10^{24}) molecules of Iron II Dichromate (FeCr₂O₇), we use Avogadro's number, which is approximately (6.022 \times 10^{23}) molecules per mole. The calculation is as follows: [ \text{Moles} = \frac{3.52 \times 10^{24} \text{ molecules}}{6.022 \times 10^{23} \text{ molecules/mole}} \approx 5.85 \text{ moles} ] Therefore, there are about 5.85 moles of Iron II Dichromate in (3.52 \times 10^{24}) molecules.
Dichromate is Cr2O7^2- so it has 7 oxygen atoms in one molecule
16 grams of oxygen how many moles is 0,5 moles.
moles of what?
2 moles of Ca and 4 moles of OH
In 2 moles of potassium dichromate, there are 16 moles of oxygen atoms (from the two oxygen atoms in each formula unit). The molar mass of oxygen is 16 g/mol, so in 2 moles of potassium dichromate, there are 32 grams of oxygen.
In potassium dichromate (K2Cr2O7), there are 7 oxygen atoms per molecule. Therefore, two moles of K2Cr2O7 would contain 14 moles of oxygen atoms. Each mole of oxygen atoms has a molar mass of approximately 16 grams, so there would be 224 grams of oxygen in two moles of potassium dichromate.
The answer is 224,141 grams oxygen.
The answer is 224,24 g oxygen.
In one mole of potassium dichromate, there seven moles of oxygen. This means in two moles of K2Cr2O7, there are 14 moles of O, or 7 Moles of O2, which equals 224 grams.
There are 6 moles of oxygen atoms in 2 moles of potassium dichromate (K2Cr2O7). Each mole of K2Cr2O7 contains 7 oxygen atoms, so 2 moles would contain 14 oxygen atoms. The molar mass of oxygen is 16 g/mol, so there would be 224 grams of oxygen in 2 moles of K2Cr2O7.
In one mole of sodium dichromate (Na2Cr2O7), there are 7 oxygen atoms. To find the number of moles in 7.00 g, you need to divide 7.00 g by the molar mass of Na2Cr2O7 to find the number of moles of Na2Cr2O7. Then, multiply the number of moles by 7 to find the number of oxygen atoms in 7.00 g of sodium dichromate.
To find the number of moles in (3.52 \times 10^{24}) molecules of Iron II Dichromate (FeCr₂O₇), we use Avogadro's number, which is approximately (6.022 \times 10^{23}) molecules per mole. The calculation is as follows: [ \text{Moles} = \frac{3.52 \times 10^{24} \text{ molecules}}{6.022 \times 10^{23} \text{ molecules/mole}} \approx 5.85 \text{ moles} ] Therefore, there are about 5.85 moles of Iron II Dichromate in (3.52 \times 10^{24}) molecules.
There are 9 oxygen atoms in 5.00 g of sodium dichromate Na2Cr2O7. This can be calculated by finding the molar mass of Na2Cr2O7 and then determining the moles of oxygen present, which is then used to find the number of atoms.
In potassium dichromate (K2Cr2O7), the molar mass is 294.18 g/mol. Therefore, 2 moles of K2Cr2O7 will contain 2 x 294.18 = 588.36 grams of the compound. Since there are 7 oxygen atoms in each molecule of K2Cr2O7, the total mass of oxygen in 2 moles will be 7 x 16 (molar mass of oxygen) x 2 = 224 grams.
Dichromate is Cr2O7^2- so it has 7 oxygen atoms in one molecule
Ammonium dichromate is a chemical compound used in pyrotechnics but does not have a direct conversion to miles. The weight of the compound is not related to distance in miles.