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How many moles of HCI do you need to react with aluminum foil if you use 15 grams of acid?
0.2550 g AlC3 (1 mol/132 g) =0.001932 mol AlCl3
0.001932 mol AlCl3 (6.022 x 10^23 molecules AlCl3/1 mol AlCl3) = 1.163 x 10^21
1.163x10^21 molecules AlCl3 (3 mol Cl/1 mol AlCl3) =3.490x10^21 Cl ions
3.490x10^21 Cl ions (1 mol/6.022 x 10^23) =5.795x10^-3 moles Cl
The formula to solve this problem appears above.
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How many grams of aluminum chloride can be made from 67.0 grams of aluminium and excess hydrochloric acid?
To determine the amount of aluminum chloride that can be produced, you need to consider the stoichiometry of the reaction between aluminum and hydrochloric acid. The balanced equation is 2Al + 6HCl → 2AlCl3 + 3H2. From the equation, 2 moles of aluminum produce 2 moles of aluminum chloride. You can use the molar mass of aluminum chloride to convert moles to grams.
How many moles of formic acid is there in 25 grams of acetic acid?
I think you meant " How many moles of acetic acid in 25 grams of acetic acid? " We will use the chemist formula for acetic acid, 25 grams C2H4O2 (1 mole C2H4O2/60.052 grams) = 0.42 mole acetic acid =================
If you need 5 moles of sulphuric acid how many grams of it will you weigh?
The mass of sulfuric acid is 490,395 grams.
How many moles of HClO4 are needed to react in excess P4O10 to produce 324.5 moles of Cl2O7?
The answer is 699 moles perchloric acid.
NiCO3 plus H2SO4 NiSO4 plus Co2 plus H2O How many grams of nickel Carbonate are needed to react with 12 grams of sulfuric acid?
To determine how many grams of nickel carbonate (NiCO₃) are needed to react with 12 grams of sulfuric acid (H₂SO₄), we first need to know the molar masses: NiCO₃ (approximately 118.7 g/mol) and H₂SO₄ (approximately 98.1 g/mol). The balanced chemical equation indicates a 1:1 molar ratio between NiCO₃ and H₂SO₄. Calculating the moles of H₂SO₄ in 12 grams gives us about 0.122 moles. Thus, we will need an equal amount of moles of NiCO₃, which corresponds to about 14.5 grams of NiCO₃ (0.122 moles × 118.7 g/mol).
How many grams of aluminum chloride can be made from 67.0 grams of aluminium and excess hydrochloric acid?
To determine the amount of aluminum chloride that can be produced, you need to consider the stoichiometry of the reaction between aluminum and hydrochloric acid. The balanced equation is 2Al + 6HCl → 2AlCl3 + 3H2. From the equation, 2 moles of aluminum produce 2 moles of aluminum chloride. You can use the molar mass of aluminum chloride to convert moles to grams.
If 44 grams of carbon react completely with 18 grams of water what is the mass of carbonic acid formed?
The molecular formula for carbonic acid is H2CO3. To find the mass of carbonic acid formed, first calculate the moles of carbon and water. Then, determine the limiting reactant and use it to calculate the moles of carbonic acid formed. Finally, convert the moles of carbonic acid to grams to find the mass.
How many grams of aluminum chloride are produced when 18 grams of aluminum are reacted with an excess of hydrochloride acid?
The empirical formula for aluminum chloride is AlCl3, and its gram formula mass is 133.34. The formula shows that each formula unit contains one aluminum atom, and the the gram atomic mass of aluminum is 26.9815. Therefore, 18(133.34/26.9815) or 89 grams, to the justified number of significant digits, of aluminum chloride will be produced.
What is the balance chemical equation for Aluminum is added to hydrochloric acid solution?
The balanced chemical equation for aluminum reacting with hydrochloric acid is: 2Al(s) + 6HCl(aq) -> 2AlCl3(aq) + 3H2(g) This equation shows that two moles of aluminum react with six moles of hydrochloric acid to produce two moles of aluminum chloride and three moles of hydrogen gas.
What The Mass Of Hydrochloric Acid Reacts With 87.7 Grams Of Aluminum Dissolves In Excess Hydrochloric Acid?
The mass of hydrochloric acid needed to react with 87.7 grams of aluminum can be calculated using stoichiometry. The balanced chemical equation for the reaction between hydrochloric acid (HCl) and aluminum (Al) is 2Al + 6HCl → 2AlCl3 + 3H2. By applying stoichiometry, you'll find that the molar mass ratio between Al and HCl is 1:6. Therefore, the amount of HCl needed to react with 87.7 grams of Al is: (87.7 grams Al) x (6 moles HCl / 1 mole Al) x (36.46 g HCl / 1 mole HCl) = 151.63 grams of HCl.
What is the maximum mass of Nitric Acid which would be required to react with 0.35 grams of copper metal?
To determine the maximum mass of nitric acid required to react with 0.35 grams of copper metal, we need to calculate the moles of copper using its molar mass. Then, we use the balanced chemical equation between copper and nitric acid to find the mole ratio between them. Finally, we convert the moles of copper to moles of nitric acid and then to grams. The maximum mass of nitric acid needed can be determined as per the stoichiometry of the balanced chemical equation.
How many moles of sodium hydroxide will react with 17 moles of sulfuric acid?
In the acid-base reaction where sodium hydroxide and sulfuric acid react, the formula is: H2SO4 + 2NaOH --> Na2SO4 + 2H2O. The coefficients shown are necessary to uphold the law of conservation of mass. So, if you have 17 moles of sulfuric acid, you will need twice as many moles of sodium hydroxide, so the answer is 34 moles NaOH.
What is the mass of hydrogen gas released from 2.70 g of aluminum metal and hydrochloric acid in grams?
I assume you mean excess hydrochloric acid. Balanced equation. 2Al + 6HCl = 2AlCl3 + 3H2 2.70 grams Al (1 mole Al/26.98 grams)(3 mole H2/2 mole Al)(2.016 grams/1 mole H2) = 0.303 grams hydrogen gas produced --------------------------------------------------
Coefficients in front of sulfurous acid plus aluminum hydroxide -- aluminum sulfite plus water?
The balanced chemical equation for the reaction between sulfurous acid and aluminum hydroxide to form aluminum sulfite and water is: 3H2SO3 + 2Al(OH)3 → Al2(SO3)3 + 6H2O This equation shows that 3 moles of sulfurous acid and 2 moles of aluminum hydroxide react to produce 1 mole of aluminum sulfite and 6 moles of water.
What is the limiting reactant of 60.0grams of aluminum present when a reaction with 25grams of hydrochloric acid occurs?
To determine the limiting reactant, we need to calculate the amount of each reactant in terms of the same unit (moles). Then, we compare the mole ratio of the reactants from the balanced chemical equation. In this case, convert 60.0 grams of aluminum to moles and 25 grams of hydrochloric acid to moles. Compare the moles of each reactant to determine the limiting reactant.
Aluminum react with sulfric acid and Which atom is oxidized?
Aluminum.
Which acid or alkali will dissolve aluminum but not nickel?
Hydrochloric acid can dissolve aluminum but not nickel. Aluminum forms a soluble aluminum chloride compound in hydrochloric acid, while nickel does not react with hydrochloric acid due to its passivation layer.
