One mole is 6.02 × 1023 of anything.
One mole of atoms is 6.02 × 1023 atoms, one mole of rice is 6.02 × 1023 grains, one mole of shoes is 6.02 × 1023 shoes. You get the picture?
One mole of molecules is 6.02 × 1023molecules.
6.02 ten to the power of 23
1.76 grams CO2 (1 mole CO2/44.01 grams)(2 mole O/1 mole CO2)(6.022 X 10^23/1 mole O2) = 4.82 X 10^22 atoms of oxygen gas
Use dimensional analysis to solve this problem. First calculate the molecular mass of CO2. This is found by (use a periodic table) adding 12.011g of C to (15.999g x2) grams of Oxygen. Once you do that, you find out that 44.009g are in 1 mole of CO2. Now, simply by looking at the equation of CO2, we can tell that 2 moles of oxygen atoms are in 1 mole of Co2 (look at the subscript for Oxygen). Now, your dimensional analysis should look like this: 254g CO2 x 1 mole CO2/44.009g CO2 x 2 mole Oxygen/1 mole CO2 The answer is 11.5 moles of Oxygen in 254g of CO2.
When 1 mole of C8H18 is burned, it forms 8 moles of CO2. Therefore, when 451 moles of C8H18 is burned, it will form 8 * 451 = 3608 moles of CO2.
Also 0,1 mole carbon dioxide.
8.066
Each mole of C2H6O will have 6.022 E23 molecules present. That means that in 3.25 moles, there are 1.957 E24 molecules present.
Since each mole of carbon dioxide molecules contains two moles of oxygen atoms, as indicated by the formula CO2 for carbon dioxide, half a mole of carbon dioxide will have one mole of oxygen atoms.
This can be calculated by using the number of Avogadro. It states that 1 mole is equal to 6.02214179*10^23 molecules. If 1 mole equals 6.02214179*10^23 molecules, then 0.0180 mole equals to: 0.0180 * 6.02214179*10^23 = 1.083985522*10^22 CO2 molecules.
6.02 ten to the power of 23
1 mol = 6.02 * 10^23 molecules 0.018 mol = 6.02 * 10^28 * 0.018 molecules 1.0836 * 10^27 molecules of CO2
2.1 moles Carbon dioxide (6.022 X 1023/1 mole CO2) = 1.3 X 1024 molecules of carbon dioxide =============================
Each mole of a substance contains 6.022 E23 molecules or atoms of that substance. Four moles of H2O will contain 2.4088 E24 molecules.
4.5166056 x 10^23 Take avagadro's number and multiply it by 0.75
2.65 mol * 64.07 g/mol = 169.79 g
To find the number of moles in 2.408 x 10^24 molecules of CO2, you can use Avogadro's number, which is approximately 6.022 x 10^23 molecules per mole. Therefore, 2.408 x 10^24 molecules / 6.022 x 10^23 molecules per mole = about 4 moles of CO2.
1 mole CO2 = 6.022 x 1023 molecules 2.4mol CO2 x 6.022 x 1023 molecules CO2/1mol CO2 = 1.4 x 1024 molecules CO2