- calculate the molar mass of the compound from the atomic weights of the elements - exactly weight this mass on a laboratory balance - put the compound in an 1 L volumetric flask - dissolve the compound in distilled (deionized) water at 20 0C; solution up to the mark - stir vigorously the solution
What volume do you want to make. To make 1 liter, you take the 185 g (the molar mass) and dissolve in enough solvent to make the final volume 1 liter.
To prepare a 1 molar solution, you would need to dissolve 180 grams of glucose powder in enough water to make a final volume of 0.5 liters.
To prepare a 1 mole solution of dimethoxyhydroxyacetophenone, you would dissolve 166.21 grams of the compound in enough solvent to make a total volume of 1 liter. Calculate the required weight based on the molar mass of dimethoxyhydroxyacetophenone (C10H12O4).
They're actually exactly the same in that neither of them exists.
Molar solution, commonly called molarity, is the amount of amount of substance in a certain volume. Typically it is measured in moles per litre. A 1 molar solution means there is one mole of substance per one litre. This can also be called a one mole concentration of solution.
What volume do you want to make. To make 1 liter, you take the 185 g (the molar mass) and dissolve in enough solvent to make the final volume 1 liter.
To prepare a 2 M solution of KCl in 1 liter of water, you would need to dissolve 149.5 grams of KCl. This is because the molar mass of KCl is approximately 74.5 g/mol, and 2 moles of KCl are needed to prepare a 2 M solution in 1 liter of water.
To prepare a 1 molar solution, you would need to dissolve 180 grams of glucose powder in enough water to make a final volume of 0.5 liters.
Dilute 1 mL of 0.5 M silver nitrate solution to a total volume of 1 L with water to make a 1 mM silver nitrate solution.
To make a 1 molar solution of sodium azide, you would need to dissolve 65.01 g of sodium azide in water to make 1 liter of solution. Since you have 98 mg of sodium azide, you would need to add enough water to make a final volume of 1 liter to create the 1 molar solution.
Find out the molecular weight of LactoseAdd that many grams of Lactose into a 1000ml volumetric flaskMake up the volume to 1000ml with waterYour 1 Molar solution of Lactose is ready---------------The molar mass of lactose is 342,3 g/mol; the solubility of lactose is 216 g/L at20 0C. Consequently you cannot prepare a molar solution of lactose.
To prepare 0.2M solution of anhydrous sodium thiosulfate (Na2S2O3), you dissolve 24.6g of anhydrous Na2S2O3 in distilled water and dilute it to 1 liter. This is the molar mass method, where molar mass of Na2S2O3 is 158.10 g/mol.
1 molar solution of sugar water contains 342,3 g sucrose.
To make a 0.1 molar solution from a 1.0 molar solution, you would dilute the original solution by a factor of 10. For example, you could mix 1 part of the 1.0 molar solution with 9 parts of solvent (like water) to achieve a final concentration of 0.1 molar.
You have to dissolve 1.00 mol, that is 98.15 g CH3COOK (its molar mass being 98.15 g/mol), in upto 1.000 L.(Suggested procedure: dissolve 98.15 g CH3COOK in not more then 900 mL, homogenize and fill up to exactly 1.000 L by carefully adding the last millilitres water).
Micromolar solution: Suppose 300 is mol wt of compound then 300g in 1000 ml -- it becomes 1M 300,000 mg in 1000 ml ---it is also 1 Molar 1 mg=1000 microgram hence 300,000,000 microgram in 1000 ml ----it is 1 molar now 300,000 microgram in 1 ml ----it is 1 Molar 1 molar=1000 milimolar hence 300,000 microgram in 1 ml -----1000 milimolar 300,000 ----------------------------- 1000,000 micromolar 0.3 microgram --in 1 ml it is 1 micromolar simillarly convert the ml as you want
To prepare a 1 mole solution of dimethoxyhydroxyacetophenone, you would dissolve 166.21 grams of the compound in enough solvent to make a total volume of 1 liter. Calculate the required weight based on the molar mass of dimethoxyhydroxyacetophenone (C10H12O4).