To determine how many moles of O2 are consumed when 309 moles of FeCr2O7 react, we first need the balanced chemical equation for the reaction. Assuming FeCr2O7 decomposes to yield Fe, Cr, and O2, a typical reaction could produce 3 moles of O2 for every mole of FeCr2O7. If this is the case, 309 moles of FeCr2O7 would consume 3 × 309 = 927 moles of O2.
To find out how many moles of FeCr2O7 are required to produce 107 moles of Fe2O3, we first need to consider the balanced chemical reaction. The reaction can be represented as: [ 2 , \text{FeCr}_2\text{O}_7 \rightarrow 2 , \text{Fe}_2\text{O}_3 + 2 , \text{Cr}_2\text{O}_3 ] From the equation, 2 moles of FeCr2O7 produce 2 moles of Fe2O3, which means 1 mole of FeCr2O7 produces 1 mole of Fe2O3. Therefore, to produce 107 moles of Fe2O3, you would need 107 moles of FeCr2O7.
10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.
When 3 moles Cu react 3 moles of copper nitrate are obtained.
4 moles also 2 moles of oxygen will be consumed
The answer is 3 moles of Cu)NO3)2..
To find out how many moles of FeCr2O7 are required to produce 107 moles of Fe2O3, we first need to consider the balanced chemical reaction. The reaction can be represented as: [ 2 , \text{FeCr}_2\text{O}_7 \rightarrow 2 , \text{Fe}_2\text{O}_3 + 2 , \text{Cr}_2\text{O}_3 ] From the equation, 2 moles of FeCr2O7 produce 2 moles of Fe2O3, which means 1 mole of FeCr2O7 produces 1 mole of Fe2O3. Therefore, to produce 107 moles of Fe2O3, you would need 107 moles of FeCr2O7.
0,25 moles lithium nitride are obtained.
To calculate the moles of C3H4 consumed, we can use the ideal gas law equation PV = nRT at STP conditions (standard temperature and pressure). Since the volume (V) is 5.6 L, and at STP conditions 1 mole of gas occupies 22.4 L, we can calculate the number of moles of C3H4 consumed as (5.6 L / 22.4 L/mol) = 0.25 moles.
10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.
When 3 moles Cu react 3 moles of copper nitrate are obtained.
How many moles of CO2 are produced when 2.1 mol of C2H2 react?
4 moles also 2 moles of oxygen will be consumed
The nunber of moles of oxygen is 2,5.
The answer is 3 moles of Cu)NO3)2..
3,44 moles H2 react with 1,146 moles NH3. The limiting reactant is hydrogen. O,244 moles N2 remain. 19,5 g NH3 are obtained.
How many moles of C are needed to react with 0.490 mole SO2?
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