To find the mass of the water that freezes, we can use the formula for the latent heat of fusion: ( Q = m \cdot L_f ), where ( Q ) is the heat released (5100 Joules), ( m ) is the mass of the water, and ( L_f ) is the latent heat of fusion for water, approximately 334,000 Joules/kg. Rearranging the formula gives ( m = \frac{Q}{L_f} ). Thus, the mass of the water is ( m = \frac{5100 , \text{J}}{334,000 , \text{J/kg}} \approx 0.0153 , \text{kg} ) or 15.3 grams.
When water freezes into ice, it releases approximately 334 joules of heat per gram. This process is known as the latent heat of fusion, which is the energy required to change water from a liquid to a solid without changing its temperature. Thus, as the lake surface freezes, each gram of water releases about 334 joules of heat into the surrounding environment.
When water freezes into ice, it releases approximately 334 joules of heat per gram. This process is known as the latent heat of fusion, which is the energy required to change water from a liquid to a solid without changing its temperature. Therefore, as the lake surface freezes in winter, each gram of water realizes 334 joules of heat.
When water freezes, each gram loses an amount of heat equal to its heat of fusion, which is approximately 334 joules per gram. This energy is released as the water transitions from a liquid to a solid state at 0 degrees Celsius. This process is crucial in regulating temperatures in natural environments, as it helps to maintain stability in ecosystems.
347 J/g.K or 83 cal are released.
Water freezes at 32 degrees Fahrenheit.
When water freezes into ice, it releases approximately 334 joules of heat per gram. This process is known as the latent heat of fusion, which is the energy required to change water from a liquid to a solid without changing its temperature. Thus, as the lake surface freezes, each gram of water releases about 334 joules of heat into the surrounding environment.
When water freezes into ice, it releases approximately 334 joules of heat per gram. This process is known as the latent heat of fusion, which is the energy required to change water from a liquid to a solid without changing its temperature. Therefore, as the lake surface freezes in winter, each gram of water realizes 334 joules of heat.
46 calories (or 192, 464 joules) for each Celsius degree.
When liquid water freezes, it releases heat to the surroundings. This is because as water cools and freezes, it is converting its energy to a lower state, thereby releasing energy in the form of heat to the surrounding environment.
When 1 gram of liquid water at 0 degrees Celsius freezes to form ice, it releases 334 Joules of heat.
The heat lost by 1 gram of water at 0 degrees Celsius as it freezes to form ice is approximately 333.55 joules. This is the heat of fusion of water, which is the energy required to change the state of water from a liquid to a solid at its melting point.
The energy released when condensing water vapor is known as the heat of condensation. It takes 2260 Joules of energy to condense 1 gram of water vapor. So, for 6.0 grams of water vapor, the energy released would be 6.0 grams * 2260 Joules/gram = 13,560 Joules.
When water freezes, each gram loses an amount of heat equal to its heat of fusion, which is approximately 334 joules per gram. This energy is released as the water transitions from a liquid to a solid state at 0 degrees Celsius. This process is crucial in regulating temperatures in natural environments, as it helps to maintain stability in ecosystems.
You have 42.5 g of water. 42.5g H20 / 18.02 g H2O (2.358 moles H2O)*(6.02 Kj/1mole H2O) = 14.1981 Kj =14.2 kJ
The energy released when 6 grams of water is condensed from water vapor is equal to the heat of vaporization of water. This is approximately 2260 joules per gram. So, for 6 grams of water, the total energy released would be around 13,560 joules.
419.1 Joules are required to heat one gram of liquid water from 0.01 degC to 100 deg C. So the answer is 419.1*46 = 19278.6
Hfus of water is 333.55 (333.55j/g)(65.8g)=21947.59J 21947.59/1000= 21.947kJ I think