0
What else can I help you with?
What is the genotype of the offspring that do not share the parents phenotype?
If both parents have the same phenotype, but the offspring did not share that phenotype, then it is likely that the parents have a dominant phenotype, but the offspring has a recessive phenotype, which means that the offpring's genotype would be homozygous recessive, and it's parents' genotypes would be heterozygous. For example, the parents may both have the genotype Bb, which gives them black fur. Approximately 25% of their offspring should have the genotype bb, which gives them the phenotype of white fur.
What are the genotypes of the parental dogs one is black the other is brown who have ONLY black or yellow puppies. Explain how you determined their genotypes.?
BBEe and bbEe. Black is dominant, and brown is recessive. Yellow is also recessive. Because one parent is brown, for none of the puppies to also be brown the black parent cannot carry the recessive allele on the B locus. Because neither parent is yellow but some of the puppies are, both parents must carry the recessive allele on the E locus.
Do black widows have egg sacs without mating?
No, black widows need to mate in order to produce fertilized eggs that will develop into viable offspring. Without mating, the eggs will not be fertilized and will not hatch into spiderlings.
When doing a genetic cross why is it necessary to remove the parent flies before the pupae have hatched?
Usually, the parent flies will have a different genotype to the F1 generation (their offspring). For example, if the parents had WW (black eyes) and ww (white eyes), their offspring would all have Ww (black eyes). If you were experimenting further, you would want the F1 generation to cross - with Ww X Ww. If you did not remove the parental generation, you could have crosses between them and the F1 generation, which would result in different genotypes. If the parents were not removed, you could have the following crosses: Ww X WW Ww X ww WW X ww Ww X Ww The only cross that you would desire in the experiment would be F1 X F1 (Ww X Ww), which would give you the desired genotypes for the F2 generation.
What two genotypes are possible for a dog that has black fur?
No. They might have the same phenotype, but would not have the same genotype.
In cocker spaniels black coat color is dominat to red Two black cockers have eight puppies 5 black and 3 red What are the genotypes of the parents?
The parents genotypes will be Black and Red. BLACK being the dominant and red the recessive. The puppies genotypes would be Black and red, Black and Black, red and red.
What was the genotype of the offspring the did not share the parents' phenotype?
If both parents have the same phenotype, but the offspring did not share that phenotype, then it is likely that the parents have a dominant phenotype, but the offspring has a recessive phenotype, which means that the offpring's genotype would be homozygous recessive, and it's parents' genotypes would be heterozygous. For example, the parents may both have the genotype Bb, which gives them black fur. Approximately 25% of their offspring should have the genotype bb, which gives them the phenotype of white fur.
What was the phenotype of the offspring that did not share of the parents phenotype?
If both parents have the same phenotype, but the offspring did not share that phenotype, then it is likely that the parents have a dominant phenotype, but the offspring has a recessive phenotype, which means that the offpring's genotype would be homozygous recessive, and it's parents' genotypes would be heterozygous. For example, the parents may both have the genotype Bb, which gives them black fur. Approximately 25% of their offspring should have the genotype bb, which gives them the phenotype of white fur.
In certain rats black fur is dominant over white fur If two rats both heterozygous for fur color are mated their offspring would be expected to have?
There different genotypes and two different colors Black fur is dominant --> F White fur is recessive --> f The parents are bot Ff (heterozygotes, and because black fur is dominant they have a black fur). If they mate, you get parents: Ff x Ff Offspring: FF Ff Ff ff so 25% will be homozygous for Black fur 2x25=50% will be heterozygous, and have a Black fur and 25% wil be homozygous for White fur. Hence, of their offspring, 75% will have a black fur and 25% will have a white fur
What is the probability of two black guinea pigs having black offspring?
depends on the two guinea pigs genotypes. could be anywhere from 75 to 100 percent.
What are some examples that illustrate the differences between incomplete dominance and codominance in genetic inheritance?
Incomplete dominance occurs when the offspring's phenotype is a blend of the parents' traits, such as when a red flower and a white flower produce pink offspring. Codominance, on the other hand, results in both parental traits being expressed equally in the offspring, like when a black chicken and a white chicken produce offspring with both black and white feathers.
In hamsters black coat color is dominant to white coat color A homozygous black hamster is mated with a heterozygous black hamster What will be the possible genotypes and phenotypes of their offspring?
The answer below should be that they will all be black: the last portion is right (3 homo. black to 1 het. black) but all the mice will have black coats. 3 black to 1 white, ......B equals black, w equals white, 3homozygous black to 1 heterozygous black.
How A Bb guinea pig crosses with a Bb guinea pig all four off springs re black how does this happen?
In guinea pigs, the black coat color is typically determined by the dominant allele (B), while the brown coat color is determined by the recessive allele (b). When two Bb guinea pigs are crossed, the possible genotypes of the offspring are BB, Bb, Bb, and bb, resulting in a 3:1 phenotypic ratio. However, if all four offspring are black, it suggests that the bb genotype did not occur, possibly due to a selection bias in the observed offspring or an error in the initial assumption about the parents' genotypes.
In guinea pigs black hair color is dominant B and white hair color is recessive b What hair color are the guinea pigs offspring?
To determine the hair color of the guinea pigs' offspring, we need to know the genotypes of the parents. If one parent is homozygous dominant (BB) and the other is homozygous recessive (bb), all offspring will be heterozygous (Bb) and will have black hair. If both parents are heterozygous (Bb), approximately 25% of the offspring are expected to be homozygous dominant (BB), 50% heterozygous (Bb), and 25% homozygous recessive (bb), resulting in a 75% chance of black hair and a 25% chance of white hair.
A female quinea pig homozygous dominant for black fur color is mated with a male homozygous for white fur In a litter of eight offspring there would probably be?
To answer this, first determine the genotypes of the parents. The female is homozygous dominant, which means it carries two copies of the black allele (which we will designate B), so its genotype we can represent as BB. The male is homozygous for the recessive trait (white, designated as b), so its genotype can be represented as bb. So the cross looks like this: BB X bb Next, we must determine the types of gametes each parent can produce. In this case it's easy, because both are homozygous. The female can only produce B gametes, while the male can only produce b gametes. Since the offspring carry one allele from each parent, all of the offspring can have only one genotype: Bb. Since black (B) is the dominant allele, and every offspring carries the dominant allele, all eight of the offspring from this cross will be black.
What will a black and a ruby eyed white gerbil produce?
Well, it depens what color the parents are and well if the black gerbil has black parents and if the ruby eyed white gerbils parents are white there babies will probably produce white and black babies.
Can two black-coated guinea pigs produce an offspring with a whit coat?
Yes
