4Al(s) + 3O2(g) --> 2Al2O3(s) where Al has an oxidation number of 3+
Cyclohexene can be formed as a byproduct in the oxidation of cyclohexanol to cyclohexanone using a strong oxidizing agent like chromic acid. Under certain conditions, cyclohexene can be further oxidized to form cyclohexanone instead of the desired product, resulting in it being a byproduct of the reaction. This undesired side reaction can occur if the reaction conditions are not carefully controlled.
At the end point, so after all Cl- has reacted with Ag+, a brown-red precipitate of silver chromate (Ag2CrO4), is formed. (Argentometric indicator)Description:The solubility of silver chromate is slightly higher than that of silver chloride. So, in a mixture of both ions silver chloride will be formed. Only when no chloride is left silver chromate will be formed and precipitated out.Prior to the endpoint the solution has a milky lemon yellow appearance, due to the color of the chromate ion and the precipitate of silver chloride already formed.When approaching the endpoint, additions of silver nitrate lead to steadily slower disappearing red colorations. When the red brownish color remains (with grayish spots of silver chloride in it) the endpoint of titration is reached. (wikipedia)
A dilute solution is formed when a small amount of solute is dissolved in a large amount of solvent. This results in a solution with a low concentration of the solute. Dilute solutions are commonly formed by adding more solvent to a concentrated solution to decrease the concentration of the solute.
If a solution is formed after the water evaporation the initial solid is obtained.
Chromate and dichromate are related as they are both chemical species containing chromium in different oxidation states. Chromate (CrO4^2-) contains chromium in the +6 oxidation state, while dichromate (Cr2O7^2-) contains chromium in the +6 and +6 oxidation states. Dichromate can be formed by the oxidation of chromate in acidic conditions. Both chromate and dichromate are commonly used as oxidizing agents in various chemical reactions.
The number of moles of silver chromate formed will depend on the stoichiometry of the reaction between silver nitrate and potassium chromate. You need to know the balanced chemical equation, as well as the exact volumes and concentrations of the silver nitrate and potassium chromate solutions to calculate the number of moles of silver chromate formed.
When sodium chromate and lead nitrate are mixed, a yellow precipitate of lead chromate is formed, along with sodium nitrate remaining in solution.
A bright yellow precipitate of lead chromate forms when potassium chromate solution is added to lead nitrate solution. This is due to the exchange of ions between the two solutions, resulting in the insoluble compound lead chromate being formed.
When potassium chromate reacts with barium sulfate, a precipitation reaction occurs. Barium chromate is formed as a yellow precipitate, while potassium sulfate remains in solution. This reaction can be used to detect the presence of sulfate ions in a solution.
To find the limiting reactant, calculate the moles of silver nitrate and potassium chromate. Convert the limiting reactant to moles of silver chromate using the balanced chemical equation. Here, 2 moles of silver nitrate react with 1 mole of potassium chromate to form 2 moles of silver chromate. Calculate the moles of silver chromate that can be formed based on the limiting reactant.
The compound formed by lead (II) and chromate ions is lead(II) chromate, with the chemical formula PbCrO4.
The precipitate formed from the reaction between barium chloride and potassium chromate is a yellow solid known as barium chromate.
The formula for the compound formed between ammonium (NH4+) and chromate (CrO4^2-) is (NH4)2CrO4.
In this reaction, the precipitate formed would be silver chromate due to the double displacement reaction between sodium chromate (Na2CrO4) and silver nitrate (AgNO3). Silver chromate is insoluble in water, so it will precipitate out of the solution as a solid, appearing as a yellow precipitate.
Lead ions = Pb2+Chromate ions = CrO4-2Compound they form is Lead(II) chromate = PbCrO4
Lead ions = Pb2+Chromate ions = CrO4-2Compound they form is Lead(II) chromate = PbCrO4