Formula: CH3I
Yes, CH3I can undergo iodoform reaction when treated with a strong base like NaOH to form iodoform (CHI3) along with other byproducts.
No its not polar
Nonpolar
IOF5 is polar - O has a double bond
CH3I is polar due to the difference in electronegativity between carbon, hydrogen, and iodine atoms. The iodine atom is more electronegative than carbon and hydrogen, creating an uneven distribution of electron density within the molecule, resulting in a net dipole moment.
CH3I exhibits dipole-dipole interactions due to the presence of a polar covalent bond between carbon and iodine. Additionally, it may also experience some weak dispersion forces.
Formula: CH3I
CH3I exhibits covalent bonding, with the carbon and hydrogen atoms sharing electrons to form bonds. The iodine atom is connected via a polar covalent bond, in which the electrons are not shared equally between the carbon and iodine atoms.
Formula: CH3I
The reaction between NaNH2 and CH3I proceeds through a nucleophilic substitution reaction, where the NaNH2 acts as a nucleophile attacking the carbon atom in CH3I, leading to the formation of a new compound and the release of sodium iodide as a byproduct.
Yes, CH3I can undergo iodoform reaction when treated with a strong base like NaOH to form iodoform (CHI3) along with other byproducts.
The reaction between CH3I and CH3COONa would result in the formation of CH3COCH3 (acetone) and NaI. This is known as a nucleophilic substitution reaction where the iodine in CH3I is replaced by the acetate group from CH3COONa.
CI2 is a nonpolar molecule. This is because the two chlorine atoms in CI2 have the same electronegativity, causing the molecule to have a symmetrical distribution of electrons, resulting in no net dipole moment.
Since there is 4 electron domains which are all single bonds without any lone pairs, the molecular geometry is tetrahedral.
No its not polar
Polar contains polar. Non-polar contains nothing.