The odds depend on the specific sex-linked disorder. For carrier mothers of an X-linked recessive disorder, there is a 50% chance of passing the affected gene to a son (who would be affected) and a 50% chance of passing the gene to a daughter (who would be a carrier). For X-linked dominant disorders, there is a 50% chance of passing the gene to both sons and daughters.
It depends on the type of disorder being discussed. For X-linked recessive disorders, a female with one copy of the mutated allele (being heterozygous) will typically be a carrier but not exhibit symptoms of the disorder. However, for autosomal dominant disorders, having one copy of the allele is sufficient for the individual to express the disorder. Therefore, the specifics of the allele and disorder in question are crucial for an accurate answer.
In the female carrier of a sex-linked disorder, there would typically be one normal allele and one mutated allele for the gene associated with the disorder on the X chromosome. This is because females have two X chromosomes, and one copy of the X chromosome with the mutated allele can be masked by the normal allele on the other X chromosome.
Haemophilia is a recessive, X-based disorder. The woman in your question is a carrier, meaning she has the defective gene, but isn't bothered by it. Therefor, the woman is of the type 'Xx'. The man is of the type 'XY', not carrying the defective gene. Their children can then be: XX, xX, XY, xY. This means that their daughters won't be affected by it, but might carry it, and their sons either not carry it at all, or carry it and be haemophilic.
An x linked disorder that causes malformattion of the skull is
Haemophilia is a sex-linked recessive disorder - which means it can skip a generation, but only if it is carried in the female line.A female can be a carrier of haemophilia, but a male cannot. This is because males only have one X chromosome, so if they have a defective X they will have the disorder. If a father has haemophilia, all of his daughters will also have haemophilia.
Usually female.
A female with one copy of the allele will be a carrier, but not have the disorder.
No.
When a female is heterozygous i.e. she possess one allele of disease , she is called carrier .
An X linked carrier is one who carries a mutation in a gene found on the X sex chromosome. A carrier of the trait doesn't display phenotypic symptoms of the disease or mutation but can transfer the mutation in that gene to their offspring (ex: the carrier of a premutation that when transferred to the offspring via the X chromosome will cause the full mutation associated with that gene). A person could be a homozygous carrier if for instance, she were female (two X chromosomes) and carried the premutation associated with the disease. Some diseases need both alleles of the gene to be mutated. If only one allele is mutated (heterozygote) that person may be a carrier for that mutation and can thus pass on that mutation to their children.
If it occurs most commonly in males, or if the mother is a carrier.
It depends on the type of disorder being discussed. For X-linked recessive disorders, a female with one copy of the mutated allele (being heterozygous) will typically be a carrier but not exhibit symptoms of the disorder. However, for autosomal dominant disorders, having one copy of the allele is sufficient for the individual to express the disorder. Therefore, the specifics of the allele and disorder in question are crucial for an accurate answer.
Hemophilia is a X linked recessive disorder. Usually the mother is an unaffected carrier and her son unfortunately receives the X chromosome in which hemophilia is linked to.
In the female carrier of a sex-linked disorder, there would typically be one normal allele and one mutated allele for the gene associated with the disorder on the X chromosome. This is because females have two X chromosomes, and one copy of the X chromosome with the mutated allele can be masked by the normal allele on the other X chromosome.
Carrier-linked drugs are often activated through hydrolysis.
The different types of carrier-linked prodrugs are bipartite, tripartite, and mutual. Bipartite structures consist of a carrier linked to a prodrug. Tripartite structues have a carrier linked to a drug via a linker. Mutual structures have two drugs linked to each other.
Haemophilia is a recessive, X-based disorder. The woman in your question is a carrier, meaning she has the defective gene, but isn't bothered by it. Therefor, the woman is of the type 'Xx'. The man is of the type 'XY', not carrying the defective gene. Their children can then be: XX, xX, XY, xY. This means that their daughters won't be affected by it, but might carry it, and their sons either not carry it at all, or carry it and be haemophilic.