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The balanced equation for the combustion of tridecane (C13H28) with oxygen (O2) can be represented as follows:

[ \text{C}{13}\text{H}{28} + 19\text{O}_2 \rightarrow 13\text{CO}_2 + 14\text{H}_2\text{O} ]

This equation shows that one molecule of tridecane reacts with nineteen molecules of oxygen to produce thirteen molecules of carbon dioxide and fourteen molecules of water.

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