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What is the mass of strontium chloride that reacts with 300 g of sulfuric acid?
To determine the mass of strontium chloride that reacts with 300 g of sulfuric acid, you need to know the balanced chemical equation for the reaction between strontium chloride and sulfuric acid. From the equation, you can determine the mole ratio between strontium chloride and sulfuric acid. Then, you can use the molar mass of strontium chloride to calculate the mass that reacts with 300 g of sulfuric acid.
How many moles are in 300mg of aspirin?
To find the number of moles in 300mg of aspirin, you need to divide the mass by the molar mass of aspirin. The molar mass of aspirin is approximately 180.2 g/mol. So, 300mg is equal to 0.3g, and dividing 0.3g by 180.2 g/mol gives you approximately 0.0017 moles of aspirin.
What is the density of an object have a mass of 54 and a volume of 300?
To calculate the density of an object, divide the mass (54) by the volume (300). The answer is about 5.
What planet has a mass more than 300 times greater than the mass of Earth?
jupiter
What is the density of gas at 1 bar pressure and 300 celsius?
At these conditions, the ideal gas law should give a very good prediction of molar density of a gas. Solving the ideal gas law for molar density you get: n/V = P/RT For the stated conditions this means n/V = (1 bar)/[(8.3144622 x 10-5 m3 bar K−1 mol−1)(300 +273.15)K] = 20.98445 moles/m3 Note that it is impossible to calculate the mass density of the gas unless you specify the composition of the gas.
What is the molarity of a 3000 liters solution containing 300 grams of NaCl?
Molarity = moles of solute/Liters of solution Find moles NaCl 300 grams NaCl (1 mole NaCl/58.44 grams) = 5.13347 moles NaCl Molarity = 5.13347 moles NaCl/3000 Liters = 1.71 X 10^-3 M sodium chloride ----------------------------------------
Approximately how many moles are in 300 grams of sulfur?
To determine the number of moles in 300 grams of sulfur, you need to know the molar mass of sulfur. The molar mass of sulfur is 32.06 g/mol. You can calculate the number of moles by dividing the given mass by the molar mass: 300 g / 32.06 g/mol ≈ 9.35 moles.
How many moles are in 300 grams of calcium sulfide?
To determine the number of moles in 300 grams of calcium sulfide, first calculate the molar mass of calcium sulfide (CaS). The molar mass of CaS is 40.08 g/mol (for calcium) + 32.06 g/mol (for sulfur), which equals 72.14 g/mol. Next, divide the given mass by the molar mass to find the number of moles: 300 g / 72.14 g/mol ≈ 4.16 moles.
What is mass of the object if its volume is 300 and density is 201 gr milliliter 5001gr milliliter?
We assume the volume is 300 ml (the question does not show that). 300 ml of 201 gr per ml = 300 x 201 = 60300 grammes = 60.30 kg. 300 ml of 5001 gr per ml = 300 x 5001 = 1500300 grammes = 1500.30 kg. Are you sure you did not mean densities of 20 and 500? The mass will then be 6kg and 150kg.
How many moles in 300.0g S?
To find the number of moles in 300.0g of sulfur (S), divide the mass in grams by the molar mass of sulfur. The molar mass of sulfur is approximately 32.06 g/mol. Therefore, 300.0g of sulfur is equal to 300.0g / 32.06 g/mol = 9.36 moles of sulfur.
What is the mass of strontium chloride that reacts with 300 g of sulfuric acid?
To determine the mass of strontium chloride that reacts with 300 g of sulfuric acid, you need to know the balanced chemical equation for the reaction between strontium chloride and sulfuric acid. From the equation, you can determine the mole ratio between strontium chloride and sulfuric acid. Then, you can use the molar mass of strontium chloride to calculate the mass that reacts with 300 g of sulfuric acid.
What is the approximate molar mass of a molecular solute if 300 g of the solute in 1000 g of water causes the solution to have a boiling point of 101C?
The change in boiling point can be used to calculate the molality of the solution. Using that molality value, you can then calculate the moles of the solute in 300g. Finally, dividing the mass by the moles gives the molar mass, which is approximately 150 g/mol.
Why is 0.9 NaCl osmolarity 300 mOsmL calculations?
- 0,9 g/L NaCl equal to 0,154 moles - but because NaCl is dissociated in two ions in water the relation is 1 mol NaCl equal 2 osmol/L - and so 0,9 % NaCl equal 308 milliosmole/L
How many atoms are in 300 grams of gold?
There are approximately 1.93 x 10^23 atoms in 300 grams of gold. This is calculated using Avogadro's number (6.022 x 10^23 atoms/mole) and the molar mass of gold (197 grams/mole).
How to calculate the percentage of NaCl to M and mOsm?
9 g/L NaCl = 0,9 g/100 mL = 0,154 moles/L = 300 mOsm/L
Would a horse have mass of 300 grams or 300 kilgrams?
300 kilograms
How many grams of sodium chloride is in 0.40 moles?
Molarity = moles of solute/Liters of solution ( 300 ml = 0.300 Liters ) For our purposes, Moles of solute = Liters of solution * Molarity Moles NaCl = 0.300 Liters * 0.15 M = 0.05 moles NaCl =============
