It is the reverse: Np-235 decay to U-235 by electron capture.
You get this answer by performing the following: Mass # Mass # 4 Atomic # Parent symbol -> Atomic # Daughter symbol + 2 He 238 234 4 92 U -> 90 Th + 2 He Both sides must equal the same thing, so if you figure out what plus 4 = 238 and what plus 2 = 92, you can figure out the element is formed through decay. The resulting element in this case is Thorium.
The chemical symbol of uranium is U.
The correct order of nuclear decay mode for the changes from U-238 to U-234 is alpha decay followed by beta decay. In alpha decay, the nucleus emits an alpha particle, reducing its atomic number by 2 and mass number by 4, resulting in Th-234. This is followed by beta decay, where a neutron is converted into a proton, producing U-234.
No, Uranium-235 and uranium-238 are radioactive, natural isotopes (not molecules, but atoms) of the one and the same element: uranium.Both with 92 protons and 235-92 = 143 neutrons in U-235 but 146 neutrons in U-238.
The daughter isotope of Pu-239 is U-235.
It is the reverse: Np-235 decay to U-235 by electron capture.
235/92 U + 1/0 n ---> 140/52 Te + 94/40 Zr + 3 1/0 n + energy
You get this answer by performing the following: Mass # Mass # 4 Atomic # Parent symbol -> Atomic # Daughter symbol + 2 He 238 234 4 92 U -> 90 Th + 2 He Both sides must equal the same thing, so if you figure out what plus 4 = 238 and what plus 2 = 92, you can figure out the element is formed through decay. The resulting element in this case is Thorium.
The decay equation for uranium-238 (U-238) decaying into an alpha particle (helium-4) can be represented as follows: (^{238}{92}\text{U} \rightarrow ^{4}{2}\text{He} + ^{234}_{90}\text{Th}). This equation shows the radioactive decay process of U-238 into an alpha particle and thorium-234.
Alpha
The equation for the alpha decay of 233Pu:94233Pu --> 92229U + 24He2+where the alpha particle is represented as a helium nucleus.Note that 233Pu decays by alpha decay with a probability of only 0.12%. The other 99.88% is Beta+ decay.
The equation for the alpha decay of plutonium-244 is: [ ^{244}{94}Pu \rightarrow ^{240}{92}U + ^4_2He ]
The chemical symbol of uranium is U.
Uranium-235 has 92 protons and 92 electrons. This is because the number of protons in an atom is equal to its atomic number, which is 92 for uranium. The number of electrons is also equal to the number of protons in a neutral atom.
The correct order of nuclear decay mode for the changes from U-238 to U-234 is alpha decay followed by beta decay. In alpha decay, the nucleus emits an alpha particle, reducing its atomic number by 2 and mass number by 4, resulting in Th-234. This is followed by beta decay, where a neutron is converted into a proton, producing U-234.
When U-235 emits a beta particle, it undergoes beta decay, transforming into Neptunium-235 (Np-235). During this process, a neutron in the nucleus of U-235 is converted into a proton, releasing a beta particle in the form of an electron and an antineutrino.