To provide the complete ionic equation, we first need to know what reaction 2 KOH is involved in. For example, if KOH is reacting with HCl, the balanced molecular equation would be:
[ \text{2 KOH (aq) + 2 HCl (aq) } \rightarrow \text{ 2 KCl (aq) + 2 H}_2\text{O (l)} ]
The complete ionic equation would be:
[ \text{2 K}^+ (aq) + \text{2 OH}^- (aq) + \text{2 H}^+ (aq) + \text{2 Cl}^- (aq) \rightarrow \text{2 K}^+ (aq) + \text{2 Cl}^- (aq) + \text{2 H}_2\text{O (l)} ]
In this case, the K⁺ and Cl⁻ ions are spectator ions and can be omitted from the net ionic equation.
The ionic product of the reaction between hydrogen gas (H₂) and potassium hydroxide (KOH) is not a standard term, as H₂ does not directly react with KOH in an ionic manner. Instead, KOH dissociates in water to form K⁺ and OH⁻ ions. If you are referring to the solubility product or a specific reaction involving these compounds, please clarify for a more accurate response.
Here is the skeleton equation: (NH4)2SO4 + KOH --> K2SO4 + NH3 + H2O And here is the balanced equation: (NH4)2SO4 + 2KOH --> K2SO4 + 2NH3 + 2H2O Here is the net ionic equation: NH4+ (aq) + OH- (aq) ---> NH3 (g) + H2O (l)
The reaction between selenium dioxide and aqueous potassium hydroxide forms selenites, or salts containing the SeO3^2- ion, and water. This reaction can be represented as SeO2 + 2KOH + H2O → K2SeO3 + H2O.
This is a double replacement reaction.
There is no real "net ionic" equation, as KI is a catalyst that decomposes H2O2. The "slow step" is H2O2 + I- --> OI- + H2O The "fast step" is H2O2 + OI- --> H2O + I- O2 The overall is: 2 H2O2 --> 2H2O + O2
The net ionic equation for the reaction between 2KOH and H2SO4 to form K2SO4 and water is: 2OH- + 2H+ -> 2H2O
2K+ + OH- + 2H+ + SO42- 2H2O(l) + 2K+ + SO4 2-
2K+ + OH- + 2H+ + SO42- 2H2O(l) + 2K+ + SO4 2-
This equation is simply 2 OH-1 (aq) + 2 H+1 (aq) -> 2 H2O.
HP- + H2O(l) ⇌ P2-(aq) + H3O+(aq)
Answer this question… OH- + 2H+ 2H2O(l)
H2SO4 + 2KOH = K2SO4 + 2H2O
The net ionic equation when potassium hydroxide and sulfuric acid are mixed is: 2K+ + 2OH- + H+ + SO4^2- -> 2H2O + K2SO4. This equation shows the key ions involved in the reaction that result in the formation of water and potassium sulfate.
2K+ + OH- + 2H+ + SO42- 2H2O(l) + 2K+ + SO4 2-
Potassium oxide(K2O) + water(H2O) --> potassium hydroxide(2KOH)
The chemical equation for the reaction between potassium oxide (K2O) and water (H2O) is: K2O + H2O → 2KOH In this reaction, potassium oxide reacts with water to form potassium hydroxide. The potassium oxide molecule (K2O) reacts with water (H2O) to produce two molecules of potassium hydroxide (2KOH).
The chemical equation for the reaction between potassium hydroxide (KOH) and sulfuric acid (H2SO4) is: 2KOH + H2SO4 → K2SO4 + 2H2O.