Here is the skeleton equation: (NH4)2SO4 + KOH --> K2SO4 + NH3 + H2O And here is the balanced equation: (NH4)2SO4 + 2KOH --> K2SO4 + 2NH3 + 2H2O Here is the net ionic equation: NH4+ (aq) + OH- (aq) ---> NH3 (g) + H2O (l)
The reaction between selenium dioxide and aqueous potassium hydroxide forms selenites, or salts containing the SeO3^2- ion, and water. This reaction can be represented as SeO2 + 2KOH + H2O → K2SeO3 + H2O.
This is a double replacement reaction.
There is no real "net ionic" equation, as KI is a catalyst that decomposes H2O2. The "slow step" is H2O2 + I- --> OI- + H2O The "fast step" is H2O2 + OI- --> H2O + I- O2 The overall is: 2 H2O2 --> 2H2O + O2
The answer is one mole.
The net ionic equation for the reaction between 2KOH and H2SO4 to form K2SO4 and water is: 2OH- + 2H+ -> 2H2O
2K+ + OH- + 2H+ + SO42- 2H2O(l) + 2K+ + SO4 2-
2K+ + OH- + 2H+ + SO42- 2H2O(l) + 2K+ + SO4 2-
This equation is simply 2 OH-1 (aq) + 2 H+1 (aq) -> 2 H2O.
HP- + H2O(l) ⇌ P2-(aq) + H3O+(aq)
Answer this question… OH- + 2H+ 2H2O(l)
H2SO4 + 2KOH = K2SO4 + 2H2O
2K+ + OH- + 2H+ + SO42- 2H2O(l) + 2K+ + SO4 2-
The net ionic equation when potassium hydroxide and sulfuric acid are mixed is: 2K+ + 2OH- + H+ + SO4^2- -> 2H2O + K2SO4. This equation shows the key ions involved in the reaction that result in the formation of water and potassium sulfate.
Potassium oxide(K2O) + water(H2O) --> potassium hydroxide(2KOH)
The chemical equation for the reaction between potassium oxide (K2O) and water (H2O) is: K2O + H2O → 2KOH In this reaction, potassium oxide reacts with water to form potassium hydroxide. The potassium oxide molecule (K2O) reacts with water (H2O) to produce two molecules of potassium hydroxide (2KOH).
The chemical equation for the reaction between potassium hydroxide (KOH) and sulfuric acid (H2SO4) is: 2KOH + H2SO4 → K2SO4 + 2H2O.