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To provide the complete ionic equation, we first need to know what reaction 2 KOH is involved in. For example, if KOH is reacting with HCl, the balanced molecular equation would be:

[ \text{2 KOH (aq) + 2 HCl (aq) } \rightarrow \text{ 2 KCl (aq) + 2 H}_2\text{O (l)} ]

The complete ionic equation would be:

[ \text{2 K}^+ (aq) + \text{2 OH}^- (aq) + \text{2 H}^+ (aq) + \text{2 Cl}^- (aq) \rightarrow \text{2 K}^+ (aq) + \text{2 Cl}^- (aq) + \text{2 H}_2\text{O (l)} ]

In this case, the K⁺ and Cl⁻ ions are spectator ions and can be omitted from the net ionic equation.

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1mo ago

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