BB's are not all made of the same materials. Some of the best are nearly pure copper. The density of copper is 8,920 kg/m3. Your instructor probably has some BB's and lab equipment he expects you to use to determine their density. Measure a BB and calculate it's volume. Weigh it and and convert your measurements into kg/m3.
BB. Bb Bb. bb
The chance of a particular trait being inherited. For each trait there are several alleles, some are dominant and others recessive, for example brown eyes are dominant over blue. The recessive phenotype can only have a genotype with both recessive alleles eg. bb The dominant phenotype can have a genotype with both dominant alleles eg. BB or one of each eg. Bb A punnet square shows the likelihood of a phenotype being inherited from given genotypes, alleles etc... BB and Bb makes BB BB Bb Bb All offspring will have the dominant phenotype (BB or Bb) eg. brown eyes Bb and Bb makes BB Bb Bb bb One in four of the offspring will have the recessive phenotype (bb) eg. blue eyes
BB or BO
To calculate the probability of a homozygous dominant (BB) offspring from a cross between two rabbits, we need to consider their genotypes. If both parents are heterozygous (Bb), the possible offspring genotypes would be BB, Bb, Bb, and bb, giving a probability of 1 out of 4, or 25%, for a homozygous dominant (BB) offspring. If one parent is homozygous dominant (BB) and the other is heterozygous (Bb), the probability of BB offspring is 1 out of 2, or 50%.
There are two types of genes that brown eyed people can have. There is BB, and Bb. The blue eyed gene is bb. If two people are Bb, and they have a child, if the child receives the two bb from each person, then they will have blue eyes.
BB. Bb Bb. bb
Bb, Bb, C, Bb, Eb, D Bb, Bb, C, Bb, F, Eb Bb, Bb, Bb(up an octave), G, Eb, D, C Ab, Ab, G, Eb, F, Eb
Bb Bb C Bb Eb D Bb Bb C Bb F Eb Bb Bb Bb G Eb D C Ab Ab G Eb F Eb
a, a, a, a, a, a, a, c, f, g, a, bb, bb, bb, bb, bb, a, a, a, a, g, g, g, a, g, c a, a, a, a, a, a, a, c, f, g, a, bb, bb, bb, bb, bb, a, a, a, a, c, c, bb, g, f. The key is F Major
Bb Eb Bb Eb Bb Eb Bb Dm7 Gm7 Cm7 F7 Bb Eb Bb Eb Bb Eb Bb
Bb Bb C Bb Eb D Bb Bb C Bb F Eb Bb Bb G F Eb D C Eb Eb D Bb C Bb
In a BB x bb cross, all offspring will have the genotype Bb. The offspring will exhibit the dominant trait of the B allele.
bbbbbb bbbbbb bbbbbb bbbbbb bbbbbb bbbbbb bbbbbb bbbbbb bbbbbb bbbbbb bbbbbb bbbbbb bbbbbb bbbbbb bbbbbb bbbbbb bbbbbb bbbbbb bbbbbb bbbbb bbbb bbbb bb bb bbbb bb bb bb bb bb bb bb bbbb bb bb bbb bb bb bb bb bb b bb b bbbbb bb bb bb b b b bbbbb
Recorder: For One And AllAA BB AA GG AA BB A B A AA BB AA GG AA BB A B A BB BB AA G G BB B A A G A BB BB AA G G BB B A A G A AA BB AA GG AA BB A B A AA BB AA GG AA BB A B A
To determine the probability of different offspring from the cross of genotypes BB, Bb, and bb, we first need to clarify the specific cross being made. If we are crossing BB (homozygous dominant) with Bb (heterozygous), the potential offspring would be 50% BB and 50% Bb. If we then cross this with bb (homozygous recessive), the resulting offspring would be 50% Bb and 50% bb. Thus, the probabilities for the offspring would be 50% Bb and 50% bb.
It's heterozygous. Heterozygous is when there is a big letter and a little letter, like Bb. Homozygous is when both letters are the same size, like BB or bb.
Bb, Bb, C, Bb, Eb, D Bb, Bb, C, Bb, F, Eb Bb, Bb, Bb(up an octave), G, Eb, D, C Ab, Ab, G, Eb, F, Eb