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in the pn junction depeletion region will be created due to equlibrium,

it ve immopile ion (+&-) ,bt it've some small amount of charge.

because hr electron &hole was nrly located,bt they are immobile,bt it ve some amount of charge .

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What Depletion region will form?

A depletion region will form at the junction of a p-type and n-type semiconductor in a semiconductor diode. This region is depleted of charge carriers, creating an electric field that prevents further flow of current in the reverse bias direction.


If the impurity concentration increasedhow depletion width effected?

As impurity concentration increases in a semiconductor, the depletion width generally decreases. This occurs because higher impurity levels enhance the charge carrier concentration, which allows the electric field to more effectively counteract the diffusion of carriers, narrowing the depletion region. Essentially, more dopants lead to a stronger electric field that limits the extent of the depletion zone.


How the depletion width effected If the impurity concentration is incresed?

As impurity concentration increases in a semiconductor, the depletion width decreases. This is because a higher concentration of dopants leads to a greater number of charge carriers, which enhances the electric field within the depletion region. Consequently, the potential barrier is more effectively neutralized, resulting in a thinner depletion layer. This effect is critical in determining the electrical characteristics of semiconductor devices like diodes and transistors.


What is the region in which a charged particle still experiences an electric force called?

The region in which a charged particle still experiences an electric force is called the electric field. An electric field is created by charged objects and extends into the space around them, influencing other charged particles within that region. The strength and direction of the electric field can vary depending on the distance from the source charge.


What happens to the electric field around a single charge when another chrage is added to the system?

When another charge is added to the system, the electric field due to the first charge will be affected. The electric field will combine or interfere with the new charge's field, resulting in a new overall electric field in the region. The strength and direction of the electric field at a point will be determined by the superposition of the fields due to each individual charge.

Related Questions

How does the depletion region in field effect transistor increases when forward biased?

Because the bulk charge and surface charge interacting with electric field (forward bias) creates the depletion region.


What Depletion region will form?

A depletion region will form at the junction of a p-type and n-type semiconductor in a semiconductor diode. This region is depleted of charge carriers, creating an electric field that prevents further flow of current in the reverse bias direction.


Why charge carriers are not present in depletion region of am pn junction?

depletion region is formed only after recombination of holes and electrons..so in depletion region there are only and only immoble positive and nagative ions...hence,there is no charge carrier..


Why depletion layer width at the collector junction are more than the depletion layer width at the emitter junction?

The depletion layer width at the collector junction is typically wider than that at the emitter junction due to the differences in doping concentrations. The collector region is generally lightly doped compared to the heavily doped emitter region, resulting in a larger electric field and a broader depletion region. Additionally, the collector junction must accommodate a higher reverse bias, which further expands the depletion region to maintain charge neutrality and facilitate efficient charge separation.


Where does the charge concentrate in a semiconductor?

In a semiconductor, the charge concentrates at the bounds of the space charge region(depletion layer).


What is another name for depletion mode transistor?

depletion layer depletion zone juntion region space charge region bipolar transistor field effect transistor variable capacitance diode


If the impurity concentration increasedhow depletion width effected?

As impurity concentration increases in a semiconductor, the depletion width generally decreases. This occurs because higher impurity levels enhance the charge carrier concentration, which allows the electric field to more effectively counteract the diffusion of carriers, narrowing the depletion region. Essentially, more dopants lead to a stronger electric field that limits the extent of the depletion zone.


Why depletion region is small in germanium compared to silicon?

The depletion region is smaller in germanium compared to silicon because germanium has a lower bandgap energy, meaning that charge carriers can easily cross the depletion region and recombine on the other side. This results in a smaller built-in potential and a smaller depletion region in germanium.


What is the difference between junction capacitance and diffusion capacitance?

Junction capacitance occurs at the depletion region of a p-n junction diode and is associated with the charge storage due to the electric field created by the built-in potential; it varies with the applied voltage. In contrast, diffusion capacitance is related to the charge carriers' movement across the junction when the diode is forward-biased, and it reflects the transient response of the charge carriers as they diffuse into the depletion region. Essentially, junction capacitance is linked to the static electric field, while diffusion capacitance is dynamic, arising from the flow of charge carriers.


How can one determine the electric field in a given region using the keyword "how to find electric field"?

To determine the electric field in a given region, you can use the formula for electric field strength, which is E F/q, where E is the electric field strength, F is the force acting on a charge, and q is the charge. By calculating the force acting on a charge in the region and dividing it by the charge, you can find the electric field strength in that region.


Why deplition region is small in germanium?

The depletion region in germanium is small because germanium has a lower band gap compared to silicon. This results in a higher charge carrier concentration and a narrower depletion region. Additionally, germanium has a higher intrinsic carrier concentration, leading to a smaller depletion region.


How do you barrier voltage is developed?

The integration of the electric field across the depletion region is what develops the barrier voltage.