74.2 times na(23)=3.22608 Na Atomic Mass=23 O ATOMIC MASS= 16 25.8 times o(16)=1.6125 how the hell does this answer the question is plastic a compound
the empirical formula of a compound tells you the proportions of the elements in the compound. with that information you can make some inferences about the identity of the compound. for example a compound with an empirical formula CH4 tells us that for every carbon atom there are four hydrogen atoms. this means that the compound is methane because no other hydrocarbon can have these roportions (try drawing the lewis structure for C2H8, which doesnt exist. you cant!)
To find the molecular formula from the empirical formula (C3H5O) and molar mass, you need to calculate the molar mass of the empirical formula. Then, divide the molar mass of the unknown compound by the molar mass of the empirical formula to get a ratio. Finally, multiply the subscripts in the empirical formula (C3H5O) by this ratio to determine the molecular formula of the unknown compound.
The empirical formula for deoxyribose is CH2O. This formula represents the simplest whole-number ratio of carbon, hydrogen, and oxygen atoms in the molecule. Deoxyribose, a sugar component of DNA, specifically contains five carbon atoms, leading to the molecular formula C5H10O4. However, its empirical formula reduces to the simplest form CH2O.
This is a hydrocarbon called Acetylene (IUPAC name : Ethyne). It contains two carbon atoms joined with a triple bond, and 2 hydrogen atoms connected to the two carbon atoms with a single bond. Its structure : H-C≡C-H
This molecular formula is C9H12.
The empirical formula of a compound is the simplest whole number ratio of the elements in the compound. In C75H25, the ratio of carbon to hydrogen is 75:25, which is equal to 3:1. Thus, the empirical formula is C3H.
The percent composition of a compound with the empirical formula CO2 is 27.3% carbon and 72.7% oxygen.
The empirical formula for the compound that is 43.6% carbon and 56.4% oxygen is CO2. This is because the ratio of carbon to oxygen in carbon dioxide is 1:2.
The empirical formula CH indicates that the compound contains one carbon atom (C) and one hydrogen atom (H) in the simplest whole number ratio. It does not provide information about the actual number of atoms present in the compound.
To find the empirical formula, we first need to convert the mass of CO2 and H2O to moles. From the molar ratios in the products, we find the moles of carbon and hydrogen present. Then, we determine the ratio of carbon to hydrogen atoms, giving the empirical formula as C7H8.
The molecular formula of a compound with an empirical formula of CH is likely to be CH, as there is only one carbon atom and one hydrogen atom in the empirical formula. In this case, the empirical formula is also the molecular formula.
The empirical formula of carbon disulfide is CS2, as it represents the simplest whole-number ratio of atoms in the compound. It consists of one carbon atom and two sulfur atoms.
aromatic hydrocarbons
The empirical formula of a compound represents the simplest whole-number ratio of atoms present in the compound. For C4H10, there is a common factor of 2 for both carbon and hydrogen, so the empirical formula would be C2H5.
the empirical formula of a compound tells you the proportions of the elements in the compound. with that information you can make some inferences about the identity of the compound. for example a compound with an empirical formula CH4 tells us that for every carbon atom there are four hydrogen atoms. this means that the compound is methane because no other hydrocarbon can have these roportions (try drawing the lewis structure for C2H8, which doesnt exist. you cant!)
The atomic mass of hydrogen is 1 and that of carbon is 12, to the nearest integer. Therefore, a compound that contains 20 percent hydrogen and 80 percent carbon contains atoms of carbon in the ratio of 20:(80/12) = 20:(20/3) = 20 X 3/20 = 3. The smallest whole number ratio corresponding to this is 1:3, which corresponds to an empirical formula of CH3. (However, since carbon normally has a valence of 4 in hydrocarbons, the actual formula is probably C2H6.)
An empirical formula contains the constituent elements in the lowest possible mathematical whole-number ratio. In some cases, this is the legitimate formula for the compound, particularly if the substance you're dealing with is an ionic compound. Sometimes, however, the actual formula, known as the molecular formula, is a whole-number multiple of the empirical formula. The molecular formula for glucose is C6H12O6. However, an empirically-derived formula for glucose would be CH2O, which is the lowest possible ratio of carbon, hydrogen, and oxygen in that compound.