Rubidium-82 decays by K Capture initiating beta+ with a half-life of 1.273 minutes decaying to Krypton-82...
3782Rb + e- --> 3682Kr + e+ + ve
The radioactive decay constant for rubidium-87 is approximately 1.42 x 10^-11 per year.
Rubidium typically loses an electron to achieve a stable electron configuration, forming a 1+ cation. This means that rubidium gains no atoms; instead, it loses an electron to become a positively charged ion.
Yes. Rubidium is an alkali metal, and all alkali metals have one valence electron.
Rubidium has one valence electron in the 5s orbital.
RbI + AgNO3 ---> RbNO3 + AgI It is displacement reaction. Rubidium is an alkali metal hence it is highly reactive and easily displaces silver from silver nitrate solution.
what is the balanced equation for Rubidium metal reacting with halogen iodine
Francium is radioactive and rubidium not. Also the electron configuration, atomic number, physical properties, hazards etc. are different.
The equation for the beta decay of 86Rb:3786Rb --> 3886Sr+ -10e where the -10e represents a beta particle or electron.
The word equation for rubidium and chlorine is: rubidium + chlorine -> rubidium chloride.
The word equation for the reaction of rubidium with water is rubidium + water --> rubidium hydroxide + hydrogen. Rubidium is a metal that reacts very quickly and fiercely, even explosively with water.
Well, you have this a little wrong. the eleectrons are involved in a chemical reaction, but are not themselves undergoing the reaction. they are the cause of a reaction and take part in it, but do not undergo a reaction. your question really is "What kind of bond does Rubidium make?" the answer to this is an ionic bond. Rubidium is an alkalai metal, and therefore ONLY creates ionic bonds. Rubidium forces its single valence electron onto another atom, at which time they each gain an electromagnetic charge. the positively charged rubidium ion is attracted to the negatively charged ion (almost definitely a non-metal, such as fluorine) causing them to be bonded.
The equation for the reaction between hydrofluoric acid (HF) and rubidium hydroxide (RbOH) is 2HF + 2RbOH → 2H2O + 2RbF, where water (H2O) and rubidium fluoride (RbF) are the products formed.
The chemical equation for perchloric acid (HClO4) reacting with aqueous rubidium hydroxide (RbOH) is HClO4 + 2RbOH → RbClO4 + 2H2O. In this reaction, perchloric acid reacts with rubidium hydroxide to form rubidium perchlorate and water.
Being an alkali metal Rubidium reacts violently with water, the reaction is similar to sodium and water but rubidium like cesium causes violent and explosive reaction with water, besides rubidium is highly reactive it gets rapidly oxidized.
Rubidium hydroxide reacts with hydrofluoric acid to produce rubidium fluoride and water. The balanced chemical equation for this reaction is 2RbOH + 2HF -> 2RbF + 2H2O.
Yes, bromine and rubidium can form an ionic compound. Rubidium can donate its outer electron to bromine, which can accept the electron to achieve a stable electron configuration. This forms rubidium bromide (RbBr), an ionic compound with rubidium ions and bromide ions held together by electrostatic forces.
When rubidium, an alkali metal, group 1, reacts it loses one electron.