243/1000 (24.3%)
To find the mass of 4 moles of magnesium chloride (MgCl2), you first need to calculate the molar mass of MgCl2. The molar mass is approximately 95.21 g/mol (24.31 g/mol for Mg and 35.45 g/mol for each Cl, with two Cl atoms). Thus, the mass of 4 moles of MgCl2 is calculated as 4 moles × 95.21 g/mol = 380.84 grams.
In one formula unit of MgCl2, there is one atom of magnesium (Mg) and two atoms of chlorine (Cl).
Hydrochloric acid + magnesium ---> Magnesium chloride + hydrogen gasUnbalanced: HCl + Mg ---> MgCl2 + H2Balanced: 2HCl + Mg ---> MgCl2 + H2
The chemical equation SiCl + Mg → MgCl2 + Si is not balanced. To balance it, you would need to adjust the coefficients to ensure that the number of atoms of each element is the same on both sides of the equation.
1
24%
The formula mass for MgCl2 (magnesium chloride) is calculated by adding the atomic masses of magnesium (Mg) and chlorine (Cl). The atomic mass of Mg is 24.31 g/mol and the atomic mass of Cl is 35.45 g/mol. Multiplying the atomic mass of Cl by 2 (since there are 2 chlorine atoms in MgCl2) and adding it to the atomic mass of Mg gives a formula mass of 95.21 g/mol for MgCl2.
The balanced chemical equation for the reaction between Mg and Cl2 to form MgCl2 is: Mg + Cl2 -> MgCl2 From the equation, it can be seen that 1 mol of Mg reacts with 1 mol of Cl2 to produce 1 mol of MgCl2. Therefore, the ratio of Cl2 to Mg in MgCl2 would be 1:1.
MgCl2 has the largest formula mass among the given compounds. This is because the formula mass of a compound is the sum of the atomic masses of all the atoms in a formula unit, and magnesium (Mg) has a greater atomic mass than lithium (Li), sodium (Na), and potassium (K).
To find the number of moles in 0.684g of MgCl2, you need to divide the mass by the molar mass of MgCl2. The molar mass of MgCl2 is 95.211 g/mol (24.305 g/mol for Mg and 35.453 g/mol for Cl). Dividing 0.684g by 95.211 g/mol gives approximately 0.0072 moles of MgCl2.
There is 9.40 mol of MgCl2 and you want to know how many grams (g). First find the atomic weight of the molecule. Mg = 24.312 Cl = 35.453 x 2 = 70.906 MgCl2 = 95.218 g/mol Then multiply the given moles by the atomic weight of the molecule to get the mass. 9.40 mol x 95.218 g/mol = 895.05 g MgCl2
The synthesis equation for MgCl2 is Mg + Cl2 -> MgCl2. The decomposition reaction is MgCl2 - heat-> Mg + Cl2.
The reaction between hydrochloric acid (HCl) and magnesium (Mg) produces magnesium chloride (MgCl2) and hydrogen gas (H2). The balanced chemical equation is 2HCl + Mg -> MgCl2 + H2.
mg + CuCl2 + MgCl2 + Cu Mg + Cu^+2 = Mg^+2 + Cu
The net equation for the reaction between MgCl2 and NaOH is: MgCl2 + 2NaOH -> Mg(OH)2 + 2NaCl
The balanced equation for the reaction between magnesium (Mg) and hydrochloric acid (HCl) is: Mg + 2HCl → MgCl2 + H2
1 mole of MgCl2=95.21 grams (found on the periodic table) 17.5 g of MgCl2(1mole of MgCl2/95.21g of MgCl2)=.184 moles of MgCl2(grams cancel out and rounded to 3 sig. figs) .184 moles of MgCl2 (1 Liter/2.5 moles of MgCl2)=0.735L of MgCl2 (moles cancel and rounded to 3 sig figs) 0.735 L of MgCl2(1000 milliLiters/1 Liter)=73.5 mL of MgCl2 and round the answer to 2 sig figs which equals 74 milliLitersof MgCl2