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To find the mass of 0.0287 moles of sucrose (C₁₂H₂₂O₁₁), you first need to know its molar mass, which is approximately 342.30 g/mol. By multiplying the number of moles by the molar mass, you calculate the mass:

0.0287 mol × 342.30 g/mol ≈ 9.81 grams.

Therefore, the mass of 0.0287 moles of sucrose is approximately 9.81 grams.

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