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What is the molecular formula of a substance that has an empirical formula of C2H5 and a molecular mass of 58 grams per mole?
The empirical formula of C2H5 corresponds to an empirical mass of 29 g/mol. To find the molecular formula from the empirical formula and molecular mass, divide the molecular mass by the empirical mass to get the "scaling factor" (58 g/mol ÷ 29 g/mol = 2). Multiply the subscripts in the empirical formula by the scaling factor to get the molecular formula: C2H5 x 2 = C4H10. So, the molecular formula is C4H10.
Calculate the molecular formulas of the compounds having the following emprical formulas and molar masses C2H5 58g mol?
To determine the molecular formula, we first need to calculate the empirical formula mass of C2H5. The empirical formula mass can be calculated by adding the molar masses of each element in the empirical formula: 2(12.01) + 5(1.01) = 29.07 g/mol. Next, divide the molar mass of the compound (58 g/mol) by the empirical formula mass (29.07 g/mol) to find the multiplier: 58 g/mol / 29.07 g/mol = 2. This multiplier gives the molecular formula of the compound, so the molecular formula is (C2H5)2 or C4H10.
Why the toluene result is higher than diethyl ether?
Molar mass of Toluene C6H5CH3 = 92.13842 g/mol Molar mass of Diethyl Eher (C2H5)2O = 74.1216 g/mol toluene is heavier
What mass of glucose must be metabolized in order to prodce 145g of water?
To determine the mass of glucose that must be metabolized to produce 145 grams of water, we can use the balanced equation for the combustion of glucose: (C_6H_{12}O_6 + 6O_2 \rightarrow 6CO_2 + 6H_2O). From the equation, 1 mole of glucose produces 6 moles of water. The molar mass of water (H₂O) is approximately 18 g/mol, so 145 g of water is about 8.06 moles (145 g / 18 g/mol). Therefore, to produce this amount of water, approximately 1.34 moles of glucose are needed (8.06 moles of water / 6). The molar mass of glucose (C₆H₁₂O₆) is about 180 g/mol, so the mass of glucose required is approximately 241.2 grams (1.34 moles × 180 g/mol).
What is the mass in grams of 0.330mol of calcium?
The mass is 0.330 mol Ca (40.08 g/mol) = 13.2 g Ca
If empirical formula is C2H5 what is molecular formula?
To find the molecular formula from the empirical formula (C2H5), we need to know the molecular mass of the compound. Since the formula implies a molecular mass of 29 g/mol (12 g/mol for carbon and 1 g/mol for hydrogen), if we divide the molecular mass of the compound by the empirical formula mass (C2H5 = 212 + 51 = 29 g/mol), we find that the molecular formula is the same as the empirical formula, C2H5.
What is the molecular formula of a substance that has an empirical formula of C2H5 and a molecular mass of 58 grams per mole?
The empirical formula of C2H5 corresponds to an empirical mass of 29 g/mol. To find the molecular formula from the empirical formula and molecular mass, divide the molecular mass by the empirical mass to get the "scaling factor" (58 g/mol ÷ 29 g/mol = 2). Multiply the subscripts in the empirical formula by the scaling factor to get the molecular formula: C2H5 x 2 = C4H10. So, the molecular formula is C4H10.
Calculate the molecular formulas of the compounds having the following emprical formulas and molar masses C2H5 58g mol?
To determine the molecular formula, we first need to calculate the empirical formula mass of C2H5. The empirical formula mass can be calculated by adding the molar masses of each element in the empirical formula: 2(12.01) + 5(1.01) = 29.07 g/mol. Next, divide the molar mass of the compound (58 g/mol) by the empirical formula mass (29.07 g/mol) to find the multiplier: 58 g/mol / 29.07 g/mol = 2. This multiplier gives the molecular formula of the compound, so the molecular formula is (C2H5)2 or C4H10.
Why the toluene result is higher than diethyl ether?
Molar mass of Toluene C6H5CH3 = 92.13842 g/mol Molar mass of Diethyl Eher (C2H5)2O = 74.1216 g/mol toluene is heavier
What mass of glucose must be metabolized in order to prodce 145g of water?
To determine the mass of glucose that must be metabolized to produce 145 grams of water, we can use the balanced equation for the combustion of glucose: (C_6H_{12}O_6 + 6O_2 \rightarrow 6CO_2 + 6H_2O). From the equation, 1 mole of glucose produces 6 moles of water. The molar mass of water (H₂O) is approximately 18 g/mol, so 145 g of water is about 8.06 moles (145 g / 18 g/mol). Therefore, to produce this amount of water, approximately 1.34 moles of glucose are needed (8.06 moles of water / 6). The molar mass of glucose (C₆H₁₂O₆) is about 180 g/mol, so the mass of glucose required is approximately 241.2 grams (1.34 moles × 180 g/mol).
What is the mass of 0.7891 mol of ferric oxide (Fe2O3)?
Atomic Mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
What is the mass of 0.7891 mol of ferric oxide Fe2O3?
Atomic mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
What is the mass of 0.7891 mol of ferric oxide?
Atomic Mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
What is the mass in grams of 0.330mol of calcium?
The mass is 0.330 mol Ca (40.08 g/mol) = 13.2 g Ca
What is the mass of 0.45 mol of ammonium sulfate?
To calculate the mass of 0.45 mol of ammonium sulfate (NH4)2SO4, you need to know its molar mass. The molar mass of (NH4)2SO4 is 132.14 g/mol. Multiply the number of moles (0.45 mol) by the molar mass to get the mass: 0.45 mol x 132.14 g/mol = 59.46 grams. Therefore, the mass of 0.45 mol of ammonium sulfate is 59.46 grams.
What is the mass of a sample containing 5.82 mol of zinc?
378.3g You multiply the RMM by the Concentration (mol) Mass(g)=Concentration(mol)*RMM
What is the mass in atoms of 350 mol of bromine?
To find the mass of 350 mol of bromine, you need to multiply the number of moles by the molar mass of bromine. The molar mass of bromine is approximately 79.9 g/mol. So, 350 mol * 79.9 g/mol = 27965 g. Therefore, the mass of 350 mol of bromine is 27965 grams.
