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1 mole of helium weighs 4.0026 g

So. 18.8 of helium will weigh 75.25 g

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Virgil Connelly

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3y ago

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What is the number of atoms in 1.88 moles of Zn?

To find the number of atoms in 1.88 moles of Zn, you would multiply the number of moles by Avogadro's number, which is 6.022 x 10^23 atoms/mol. Therefore, there are approximately 1.13 x 10^24 atoms in 1.88 moles of Zn.


With 188 garms of barium chloride there would be how much moles?

First, you want to figure out how many grams 1 mol of barium is. Look at the periodic table of elements. (www.webelements.com) Barium is Ba. Scroll down a little bit after clicking and you will see atomic weight. It is 137g. Now get the atomic weight for chlorine. It is Cl. The atomic weight is 35.5g. Just add them together. 137+35.5 = 172.5g = 1 mol of barium chloride. For 188g, just divide it by 172.5g. Which is 1.09 moles.


How many neutrons are in an Osmium atom of mass number 188?

An Osimum atom with mass number 188 has 118 protons (atomic number for Osmium). To find the number of neutrons, we subtract the atomic number from the mass number: 188 - 118 = 70 neutrons.


What is the mass of silver bromide precipitated from 2.96 g of iron bromide?

This is an incomplete question for several reasons. Iron bromide can be FeBr2 or FeBr3 and this will influence the answer. Also, in order to precipitate silver bromide, one would add silver nitrate, but it isn't stated how much silver nitrate is used. Assuming FeBr2 is used, and there is excess AgNO3, then .... 2AgNO3 + FeBr2 ----> 2AgBr(s) + Fe(NO3) moles FeBr2 = 2.96 g x 1 mol/216 g = 0.0137 moles moles AgBr produced = 2 x 0.0137 = 0.0274 moles mass AgBr produced = 0.0274 moles x 188 g/mole = 5.15 grams <---answer


How many MG is 118 ML?

188 milliliters (ml) is equal to 188 milligrams (mg). They have the same numerical value because both milliliters and milligrams are metric units of measurement, but they measure different properties. Milliliters measure volume, while milligrams measure mass. So, in this case, 188 ml is equivalent to 188 mg.


How many milliliters of a 2.00 M solution of nitric acid are needed to completely react with 15.0 g of sodium hydroxide according to the chemical reaction shown below?

The balanced chemical equation for the reaction is 2HNO3(aq) + 2NaOH(aq) → 2NaNO3(aq) + 2H2O(l). Using the given information, we first find the moles of sodium hydroxide by dividing the mass by the molar mass. Then, we use the mole ratio from the balanced equation to find the moles of nitric acid needed. Finally, we use the definition of molarity to find the volume of the solution required.


What is 188 add 188?

376


What is 60 percent of 188?

60% of 188= 60% * 188= 0.6 * 188= 112.8


What is 376-188?

564


What is 20 percent off 188 dollars?

20% of $188 = (188/100)*20 = $37.620% off $188 = (188-37.6) = $150.4


What is 188 percent as a fraction?

188% = 188/100 = 47/25


What is the percentage of 240-188?

188 of 240 is 78% n 240 of 188 is 127%