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If 5.742g of hydrated magnesium sulfate is heated 2.801g of anhydrous magnesium sulfate remains Determine the formula of the hydrated form?
The formula of the hydrated form is MgSO4·7H2O. To find this, calculate the molar mass of MgSO4 (120.37 g/mol) and compare it to the molar mass of MgSO4·7H2O (246.47 g/mol). The difference in mass represents the mass of water lost upon heating, which is 126.1 g/mol (246.47 g/mol - 120.37 g/mol). Dividing the mass of water lost by the molar mass of water (18.015 g/mol) gives us the number of water molecules in the hydrated form.
Please help me The balance formula MgSo4 2NaOH MgOH Na2SO4 125 g of MgSO4 115 g of NaOH what is the mass of milk of magnesia MgOH2 produced?
2 NaOH + MgSO4-----Mg(OH)2+Na2SO4 1 MOLE OF MgSO4 produce one mole of Mg(OH)2 SO 1 MWT OF MgSO4 PRODUCE1MWT OF Mg(OH)2 HENCE 120 GM MgSO4 PRODUCE 58 gm OF Mg(OH)2 and so on if x gm of MgSO4 PRODUCE y gm OF Mg(OH)2 x=(120*y)/58 ---- ----
Is the mass of 1mole of O and 1 mole of S same?
No; 1 mole of molcular oxygen (O2) is 31,998 g and 1 mole of sulfur (S) is 32,06 g.
How do you convert 5.2 moles of Epsom salt to grams?
The chemical formula of hydrated Epsom salt is MgSO4.7H2O. The molar mass is 246,47 grams. 5,2 X 246,47 = 1281,644 grams
Chemical formula of Magnesium sulfate?
The chemical formula of Magnesium sulfate is MgSO4.
What is the percentage mass of oxygen in MgSO4?
The molar mass of MgSO4 is 120.37 g/mol. The molar mass of oxygen is 16.00 g/mol. To find the percentage mass of oxygen in MgSO4, we divide the molar mass of oxygen by the molar mass of MgSO4 and multiply by 100 to get 47.27%.
What element is larger H2o or MgSO4?
Neither H2O nor MgSO4 are elements. They are COMPOUNDS. In terms of volume occupied , MgSO4 is the larger.
Do MgSO4 and NaCl weigh the same?
No Magnesium Sulfate (MgSO4) has a mass of 121, and Sodium Chloride (NaCl) has a mass of 59.
How many moles are present in 1.64g of MgSO4?
To calculate the number of moles in 1.64g of MgSO4, you first need to determine the molar mass of MgSO4 which is 120.37 g/mol. Next, divide the given mass by the molar mass to get the number of moles. In this case, 1.64g ÷ 120.37 g/mol ≈ 0.014 moles of MgSO4.
What mass of magnesium sulphate is needed to make 1500 ml of a 2.45 m mgso4 solution?
To find the mass of magnesium sulfate needed, first calculate the moles of MgSO4 required using the formula: moles = molarity × volume (in liters). Then, multiply the moles by the molar mass of MgSO4 (120.37 g/mol) to get the mass in grams. In this case, the mass of MgSO4 needed would be approximately 450.6 grams.
If 5.742g of hydrated magnesium sulfate is heated 2.801g of anhydrous magnesium sulfate remains Determine the formula of the hydrated form?
The formula of the hydrated form is MgSO4·7H2O. To find this, calculate the molar mass of MgSO4 (120.37 g/mol) and compare it to the molar mass of MgSO4·7H2O (246.47 g/mol). The difference in mass represents the mass of water lost upon heating, which is 126.1 g/mol (246.47 g/mol - 120.37 g/mol). Dividing the mass of water lost by the molar mass of water (18.015 g/mol) gives us the number of water molecules in the hydrated form.
Please help me The balance formula MgSo4 2NaOH MgOH Na2SO4 125 g of MgSO4 115 g of NaOH what is the mass of milk of magnesia MgOH2 produced?
2 NaOH + MgSO4-----Mg(OH)2+Na2SO4 1 MOLE OF MgSO4 produce one mole of Mg(OH)2 SO 1 MWT OF MgSO4 PRODUCE1MWT OF Mg(OH)2 HENCE 120 GM MgSO4 PRODUCE 58 gm OF Mg(OH)2 and so on if x gm of MgSO4 PRODUCE y gm OF Mg(OH)2 x=(120*y)/58 ---- ----
A hydrate is found to have the following percent composition 48.8 percent MgSO4 and 51.2 percent H2O What is the formula and name for this hydrate?
48.8 g MgSO4 & 51.2 g H2O Convert the mass into moles by dividing molar mass for each. Then obtain a ratio of moles of water over moles of Magnesium Sulfate, and you would get 7. MgSO4 . 7H2O would read as Magnesium Sulfate Heptahydrate.
What is the mass of one mole of MgSO4?
If the MgSO4 is the only oxygen containing compound in the salt, there must be four moles of oxygen atoms, and the number of atoms in 4 moles is 4 multiplied by Avogadro's number or about 2.409 X 1024 atoms.
How many moles are present in 480g of anhydrous magnesium sulfate?
First we calculate the formula mass of the compound magnesium sulfate.Formula mass of MgSO4 = 24.3 + 32.1 + 4(16.0) = 120.4 Amount of MgSO4 in a 480g pure sample = 480/120.4 = 3.99mol There is approximately 4 moles of the compound present in a 480g sample.
Mass of 0.00100 mol of caffeine?
The formula for caffeine is C8H10N4O2 and its molar mass is 194.19g/mole. 1mol caffeine = 194.19g 0.00100mole caffeine X (194.19g/1mole) = 0.19419g caffeine
What is the name of the chemical compound MgSO4?
The chemical compound MgSO4 is called magnesium sulfate.
