The mass of 3.2 moles O2? The atoms in 3.2 moles O2 Could be other things, I guess, but I will do these two. 3.2 moles O2 (32 grams/1 mole O2) = 102.4 grams of gaseous oxygen -------------------------------------------- 3.2 mole O2 (6.022 X 1023/1 mole O2) = 1.9 X 1024 atoms of gaseous oxygen --------------------------------------------------
To find the mass of O2 that will react with 400 g of C4H10, first calculate the moles of C4H10 using its molar mass. Then, using the balanced chemical equation for the reaction between C4H10 and O2, determine the mole ratio between C4H10 and O2. Finally, convert the moles of C4H10 to moles of O2 and then to grams of O2 using the molar mass of O2.
to convert an element to moles you need to setup and equation, for our example we will be using 5g of O2 or oxygen. You need to know what O2's molar mass is as well, it is 32g. So the equation would be 5g of O2 / 32 = .16 moles of O2. So to convert moles to grams all you do is multiply the moles given by the molar mass of the element/compound and you have your grams Hoped this helped : )
Calculate the molecular weight of Aspirin, by adding up the atomic weights of the atoms that make it up. Then take the mass of the tablet (325mg, divide by 1000 too) and divide by the molecular weight you just got.
The molar mass of O2 is 32 g/mol. To find the number of molecules in 48.0 grams of O2, we first need to find the number of moles using the formula: number of moles = mass / molar mass. Then, we can use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
The mass of 3.2 moles O2? The atoms in 3.2 moles O2 Could be other things, I guess, but I will do these two. 3.2 moles O2 (32 grams/1 mole O2) = 102.4 grams of gaseous oxygen -------------------------------------------- 3.2 mole O2 (6.022 X 1023/1 mole O2) = 1.9 X 1024 atoms of gaseous oxygen --------------------------------------------------
To calculate the mass of 1.5 moles of oxygen molecules (O2), you multiply the number of moles (1.5) by the molar mass of oxygen (O2). The molar mass of O2 is approximately 32 g/mol. So, the mass of 1.5 moles of oxygen molecules would be 1.5 moles * 32 g/mol = 48 grams.
To find the number of moles in 150.0 g of O2, first calculate the molar mass of O2, which is 32.0 g/mol (16 g/mol for each oxygen atom). Then, divide the given mass by the molar mass to get the number of moles: 150.0 g / 32.0 g/mol = 4.69 moles of O2.
To find the mass of O2 that will react with 400 g of C4H10, first calculate the moles of C4H10 using its molar mass. Then, using the balanced chemical equation for the reaction between C4H10 and O2, determine the mole ratio between C4H10 and O2. Finally, convert the moles of C4H10 to moles of O2 and then to grams of O2 using the molar mass of O2.
Two moles of O2 molecules would have a mass of 64 grams (2 moles x 32 grams/mole = 64 grams).
For this you need the atomic (molecular) mass of O2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.2.047 moles O2 × (32.0 grams) = 65.5 grams O2
15 moles O2 (32 grams/1 mole O2) = 480 grams
to convert an element to moles you need to setup and equation, for our example we will be using 5g of O2 or oxygen. You need to know what O2's molar mass is as well, it is 32g. So the equation would be 5g of O2 / 32 = .16 moles of O2. So to convert moles to grams all you do is multiply the moles given by the molar mass of the element/compound and you have your grams Hoped this helped : )
To determine the mass of NO2 formed when NO reacts with O2, we need to write and balance the chemical equation for the reaction. The balanced equation is 2NO + O2 -> 2NO2. From the equation, we see that 2 moles of NO will react with 1 mole of O2 to produce 2 moles of NO2. Next, we need to calculate the number of moles of O2 present in 384g using its molar mass. Finally, we can use the mole ratio from the balanced equation to find the mass of NO2 formed.
We first calculate the molar mass of P4O10, which is 284 g/mol. Then we convert the given mass of P4O10 (142 g) to moles using its molar mass. There is a 1:4 molar ratio between P4O10 and O2 in the reaction, so we multiply the moles of P4O10 by 4 to find the moles of O2 needed.
From the balanced chemical equation, 4 moles of KOH produce 1 mole of O2. Given that there are 6.21 moles of KOH, we can set up a ratio: (6.21 moles KOH) x (1 mole O2 / 4 moles KOH) = 1.5525 moles O2. Finally, using molar mass of oxygen (O2) which is 32 g/mol, we find that 1.5525 moles of O2 is equal to 49.68 grams of O2.
To determine the grams of oxygen needed to produce 4.50 moles of NO2, use the coefficients in the balanced equation. In this case, 7 moles of O2 are required to produce 4 moles of NO2. Calculate: (4.50 moles of NO2) * (7 moles of O2 / 4 moles of NO2) = 7.88 moles of O2. Finally, convert moles to grams using the molar mass of O2 (32.00 g/mol): 7.88 moles * 32.00 g/mol = 252.16 grams of O2.