To find the molarity of the solution, first, we need to determine the total volume of the solution in liters. Since the density of water is approximately 1 kg/L, 3 kg of water corresponds to about 3 liters. Molarity (M) is calculated as moles of solute divided by the volume of solution in liters. Thus, the molarity of the solution is ( \frac{6 \text{ moles}}{3 \text{ L}} = 2 \text{ M} ).
The molarity is 2 mol/L.
The molarity can be calculated using the formula: moles of solute divided by liters of solution. In this case, the moles of sucrose is 25, and the liters of solution is 50. This gives a molarity of 0.5 M.
To determine the molarity, you need to know the volume of water the 3 moles of FeBr3 are dissolved in. With this information, you can use the formula: Molarity (M) = Moles of solute / Liters of solution. Therefore, if you dissolve 3 moles of FeBr3 in 1 liter of water, the molarity would be 3 M.
The molarity is 6 mol/l.
Molarity = number of moles / number of liters. For this question the number of moles is 3 and the number of liters is 0.5 So 3/0.5 = 6 The solution is 6 M.
molarity is #moles divide by # liters, so 3.0 divided by 0.500 is 6.0 molarity (2 siginficant figures is all you are allowed)
2 m is the molarity of a solution that has 6 mol of CaCl2 in 3 km of water.
The molarity is 2 mol/L.
The molarity of the solution can be calculated by dividing the moles of solute by the volume of solution in liters. In this case, 2 moles of NaOH in 1620 mL (1.62 L) of water gives a molarity of approximately 1.23 M.
The molarity of the salt solution can be calculated by dividing the number of moles of solute (salt) by the volume of solution in liters. In this case, the molarity would be 10 moles / 20 liters = 0.5 moles per liter (M).
To make a 0.2 M CaCl2 solution with a final volume of 200 ml, you would need to dissolve 8.8 grams of calcium chloride (CaCl2) in water. This calculation is based on the molar mass of CaCl2 (110.98 g/mol) and the formula for calculating molarity (moles = molarity x volume in liters).
The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, the molarity of the solution is 3 moles / 5 L = 0.6 M.
The molarity can be calculated using the formula: moles of solute divided by liters of solution. In this case, the moles of sucrose is 25, and the liters of solution is 50. This gives a molarity of 0.5 M.
6mol/2L
Molarity = moles of solute/Liters of solution Molarity = 6 Moles NaCl/2 Liters = 3 M NaCl ========
To determine the molarity, you need to know the volume of water the 3 moles of FeBr3 are dissolved in. With this information, you can use the formula: Molarity (M) = Moles of solute / Liters of solution. Therefore, if you dissolve 3 moles of FeBr3 in 1 liter of water, the molarity would be 3 M.
This molarity is 3 M.