c12h24
The molecular formula CH2 suggests that the compound consists of carbon and hydrogen atoms. To determine the molecular formula based on the molar mass of 168 g/mol, we can calculate the molar mass of the empirical formula CH2 (which is about 14 g/mol). Dividing 168 g/mol by 14 g/mol gives us 12, indicating that the molecular formula is C12H24.
The molecular formula of the compound CH2, with a molar mass of 42.0 g/mol, indicates that it is likely a hydrocarbon with a greater number of carbon and hydrogen atoms than just one carbon and two hydrogens. Given the molar mass, the compound could be C3H6, as the molar mass of C3H6 (3 × 12.01 g/mol for carbon + 6 × 1.008 g/mol for hydrogen) is approximately 42.0 g/mol. Thus, the molecular formula of the compound is C3H6.
To determine the molecular formula from the empirical formula CFBrO, we first calculate the molar mass of the empirical formula: C (12.01 g/mol) + F (19.00 g/mol) + Br (79.90 g/mol) + O (16.00 g/mol) = 126.91 g/mol. Next, we divide the given molar mass (381.01 g/mol) by the empirical formula mass (126.91 g/mol) to find the ratio: 381.01 g/mol ÷ 126.91 g/mol ≈ 3. The molecular formula is thus (CFBrO)₃, or C₃F₃Br₃O₃.
To determine the molecular formula of the compound containing 89 cesium (Cs) and 11 oxygen (O), we first calculate the molar mass of the individual elements: Cs has an atomic mass of about 132.91 g/mol and O about 16.00 g/mol. The total mass for 89 Cs is approximately 11,800.99 g (89 x 132.91) and for 11 O is about 176.00 g (11 x 16.00), leading to a total mass of roughly 11,976.99 g. Given the molar mass of the compound is 298 g/mol, we divide the total mass by the molar mass to find the ratio of moles of each element in the compound, indicating a very large empirical formula rather than a typical molecular formula.
C5h10
c12h24
This formula is for magnesium chloride hexahydrate: MgCl2.6H2O.
The molecular formula of the compound is C2H4, which has a molar mass of 28 g/mol. Since the given compound has a molar mass of 42.0 g/mol, it must include an additional CH2 group, resulting in the molecular formula C2H6.
c12h24
The average molecular weight of dry air is 28.96 g/gmol.
The compound's empirical formula is CH3N, and its molecular formula is C4H12N. Therefore, the subscript on C in the chemical formula is 4.
c3h6
The molecular formula CH2 suggests that the compound consists of carbon and hydrogen atoms. To determine the molecular formula based on the molar mass of 168 g/mol, we can calculate the molar mass of the empirical formula CH2 (which is about 14 g/mol). Dividing 168 g/mol by 14 g/mol gives us 12, indicating that the molecular formula is C12H24.
The molar mass of the compound is 298 g/mol. To find the molecular formula, we need to calculate the molar mass of Cs and O; Cs has a molar mass of approximately 132.91 g/mol, and O has a molar mass of approximately 16 g/mol. Using these values, we can determine that the compound's molecular formula is Cs11O11.
gmol-1 refers to grams per mole and is a unit of measurement commonly used in chemistry to express molar mass or molecular weight. It represents the mass of one mole of a substance in grams.
The empirical formula of SN has a formula unit mass of the sum of the gram atomic masses of nitrogen and sulfur, i.e., about 46.0667. The gram molecular mass given in the problem divided by this formula unit mass is about 4. Therefore, the molecular formula is S4N4.