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The empirical formula of a compound is ch2its molecular mass is 70 gmol what is its molecular formula?

C5h10


What is the molecular formula of the compound CH2 with molar mass 168 gmol?

c12h24


If an unknown hydrate MgCl2 and bullxH2O has a molecular mass of 203.30 gmol what is the numeric value of x in the formula?

This formula is for magnesium chloride hexahydrate: MgCl2.6H2O.


What is the molecular formula of the compound CH2 with a molar mass 42.0 gmol?

The molecular formula of the compound is C2H4, which has a molar mass of 28 g/mol. Since the given compound has a molar mass of 42.0 g/mol, it must include an additional CH2 group, resulting in the molecular formula C2H6.


What is the molecular formula of the compound ch2 with molar mass equals 168 gmol?

c12h24


What is average molecular weight of air?

The average molecular weight of dry air is 28.96 g/gmol.


The analysis of an organic compound showed that it contains 0.175 mol C 0.140 mol H and 0.035 mol N. Its molecular mass is about 160 gmol. What is the subscript on C in the chemical formula?

The compound's empirical formula is CH3N, and its molecular formula is C4H12N. Therefore, the subscript on C in the chemical formula is 4.


What is the molecular formula of the compound CH2 with molar mass 42.0 gmol?

c3h6


What is the molecular formula of a compound containing 89 cesium (Cs) and 11 oxygen (O) with a molar mass 298 gmol?

The molar mass of the compound is 298 g/mol. To find the molecular formula, we need to calculate the molar mass of Cs and O; Cs has a molar mass of approximately 132.91 g/mol, and O has a molar mass of approximately 16 g/mol. Using these values, we can determine that the compound's molecular formula is Cs11O11.


What does gmol-1 mean?

gmol-1 refers to grams per mole and is a unit of measurement commonly used in chemistry to express molar mass or molecular weight. It represents the mass of one mole of a substance in grams.


A compound with the empirical formula SN was found in a subsequent experiment to have a molar mass of 184.32 gmol. What is the molecular formula of the compound?

The empirical formula of SN has a formula unit mass of the sum of the gram atomic masses of nitrogen and sulfur, i.e., about 46.0667. The gram molecular mass given in the problem divided by this formula unit mass is about 4. Therefore, the molecular formula is S4N4.


What is the molecular formula of a compound if its empirical formula is CFBrO and its molar mass is 381.01 gmol?

To determine the molecular formula from the empirical formula CFBrO, we first calculate the molar mass of the empirical formula: C (12.01 g/mol) + F (19.00 g/mol) + Br (79.90 g/mol) + O (16.00 g/mol) = 126.91 g/mol. Next, we divide the given molar mass (381.01 g/mol) by the empirical formula mass (126.91 g/mol) to find the ratio: 381.01 g/mol ÷ 126.91 g/mol ≈ 3. The molecular formula is thus (CFBrO)₃, or C₃F₃Br₃O₃.