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How many grams of water are needed to react with 74.0 g CaCN2?
The molar mass of CaCN2 is 80.10 g/mol. To calculate the number of moles in 74.0 g, divide the given mass by the molar mass. The balanced chemical equation for the reaction would be needed to determine the stoichiometry and amount of water required to react with 74.0 g CaCN2.
How many grams of water are needed to react with 79.0 CaCN2?
To determine the amount of water needed to react with 79.0 CaCN2, you need to use stoichiometry. The balanced chemical equation for the reaction is: CaCN2 + 3H2O -> CaCO3 + 2NH3 From the equation, you can see that 3 moles of water are needed to react with 1 mole of CaCN2. Calculate the moles of CaCN2 in 79.0 grams, then use the mole ratio to determine the moles of water needed. Finally, convert the moles of water to grams using the molar mass of water.
What is the name for the formula CaCN2?
The chemical formula CaCN2 corresponds to the compound calcium cyanamide.
Is mass percent the same as percent by mass?
Yes, mass percent and percent by mass are the same concept. Both terms refer to the percentage of a component in a mixture by mass.
Percent composition is expressed as a percent by?
Percent composition is usually expressed as a percent by mass, but in the case of gases and vapors, it is often expressed as a percent by volume.
How many grams of water are needed to react with 74.0 g CaCN2?
The molar mass of CaCN2 is 80.10 g/mol. To calculate the number of moles in 74.0 g, divide the given mass by the molar mass. The balanced chemical equation for the reaction would be needed to determine the stoichiometry and amount of water required to react with 74.0 g CaCN2.
How many grams of water are needed to react with 73.0 g CaCN2?
mass H2O =49.2g
How many grams of water are needed to react with 79.0 CaCN2?
To determine the amount of water needed to react with 79.0 CaCN2, you need to use stoichiometry. The balanced chemical equation for the reaction is: CaCN2 + 3H2O -> CaCO3 + 2NH3 From the equation, you can see that 3 moles of water are needed to react with 1 mole of CaCN2. Calculate the moles of CaCN2 in 79.0 grams, then use the mole ratio to determine the moles of water needed. Finally, convert the moles of water to grams using the molar mass of water.
What is the mass percent of n in ammonium bicarbonate?
The formula for ammonium bicarbonate is NH4HCO3. To find the mass percent of nitrogen (N), calculate the molar mass of nitrogen in the formula and divide it by the molar mass of the entire compound NH4HCO3. The molar mass of N is 14.01 g/mol, and the molar mass of NH4HCO3 is 79.06 g/mol. Therefore, the mass percent of nitrogen in ammonium bicarbonate is (14.01 g/mol / 79.06 g/mol) * 100% = 17.7%.
What is the molar weight of CaCl2?
The molar mass of CaCN2 = 80.1021 g/mol
MSG has 35.51 percent C 4.77 percent H 37.85 percent O 8.29 percent N and 13.60 percent NaWhat is its molecular formula if its molar mass is 169g?
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What is the name for the formula CaCN2?
The chemical formula CaCN2 corresponds to the compound calcium cyanamide.
Is mass percent the same as percent by mass?
Yes, mass percent and percent by mass are the same concept. Both terms refer to the percentage of a component in a mixture by mass.
What is the mass percent of nitrogen in ammonium carbonate (NH4)2CO3?
To calculate the mass percent of nitrogen in ammonium carbonate (NH4)2CO3, first find the molar mass of the compound: 2(N) + 8(H) + 1(C) + 3(O) = 96 g/mol. The molar mass of nitrogen in the compound is 2(N) = 28 g/mol. To find the mass percent of nitrogen, divide the molar mass of nitrogen by the molar mass of the compound and multiply by 100: (28 g/mol / 96 g/mol) x 100 = 29.2%.
If 15 percent of a number n is 0.3 what is 45 percent of N?
If 15 percent of a number N is 0.3 what is 45 percent of N
Bernard's star has a mass of how many times the mass of sun?
15-17 percent of the mass of the Sun.15-17 percent of the mass of the Sun.15-17 percent of the mass of the Sun.15-17 percent of the mass of the Sun.
What is the percent composition of the compound that forms when 222.6 g N combines completely with 77.4 g O?
The molar mass of nitrogen (N) is 14 g/mol, and of oxygen (O) is 16 g/mol. Calculate the number of moles of each element. The ratio of the moles of N to O is 3:1. Therefore, the percent composition of the compound is approximately 75% N and 25% O.
