NaN3 also known as Sodium azide is used as an antibacterial agent and to inflate airbags.
NaN3 decomposed to form nitrogen gas (N2) and sodium. 2NaN3 --> 2Na + 3N2
NaN3 (sodium azide) decomposes into Na (sodium) and N2 (nitrogen gas). The chemical equation is: 2 NaN3(s) → 2 Na(s) + 3 N2(g)
137 mM NaCl, 25 mM Tris-HCl [pH 7.4], 0.7 mM Na2HPO4, 5 mM KCl
The number of atoms is 45,166.10e23.
NaN2 does not have a known chemical formula. It is likely a typo or error, as the correct formula for sodium azide is NaN3. Sodium azide is commonly used in airbags and as a reagent in organic synthesis.
The empirical formula for sodium azide is NaN3.
NaN3
To calculate the total number of moles in the 52.0 gram sample of NaN3, divide the given mass by the molar mass of NaN3. First, determine the molar mass of NaN3 by summing the atomic masses of its elements (sodium, nitrogen, and three times the atomic mass of nitrogen). Then, divide the mass of the sample by the molar mass of NaN3 to find the number of moles.
NaN3 decomposed to form nitrogen gas (N2) and sodium. 2NaN3 --> 2Na + 3N2
Callod sodium acid ( NaN3 )
NaN3 (sodium azide) is an ionic compound. It is composed of sodium cations (Na+) and azide anions (N3-) which are held together by ionic bonds due to the transfer of electrons from sodium to azide.
The compound NaN3 is called sodium azide. It is commonly used as a propellant in airbags and as a reagent in organic synthesis. Sodium azide is highly toxic and should be handled with caution.
9.28 g
The chemical equation is:2 NaN3 = 2 Na + 3N2
Using the balanced chemical equation for the decomposition of sodium azide, 2NaN3 -> 2Na + 3N2, we can see that 2 moles of Na3N produce 3 moles of N2. Therefore, for 2.88 mol of NaN3, we would produce 2.88 mol * (3 mol N2 / 2 mol NaN3) = 4.32 moles of N2.
NaN3 (sodium azide) decomposes into Na (sodium) and N2 (nitrogen gas). The chemical equation is: 2 NaN3(s) → 2 Na(s) + 3 N2(g)
First, convert 13.0 ft3 to liters (1 ft3 is approximately 28.32 L). This gives approximately 368.96 L. Since the density of nitrogen gas is 1.25 g/L, the mass needed is 368.96 L * 1.25 g/L = 461.2 g. Finally, use the molar mass of NaN3 (65 g/mol) to convert grams to moles (461.2 g / 65 g/mol = 7.09 moles). Therefore, approximately 461.2 grams of NaN3 are required to produce 368.96 L of nitrogen gas.