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To determine the mass of sulfur dioxide (SO₂) produced from 4 grams of carbon (C), we first need to consider the balanced chemical reaction for the combustion of carbon in the presence of sulfur (S):
[ C + O_2 + S \rightarrow SO_2 ]
From the reaction, one mole of carbon produces one mole of sulfur dioxide. The molar mass of carbon is approximately 12 g/mol, so 4 g of carbon corresponds to ( \frac{4 , \text{g}}{12 , \text{g/mol}} \approx 0.333 , \text{mol} ) of carbon. Since the molar mass of SO₂ is about 64 g/mol, the mass of SO₂ produced would be ( 0.333 , \text{mol} \times 64 , \text{g/mol} \approx 21.33 , \text{g} ).
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How do you calculate SO2 to SO3 conversion efficiency?
SO2 to SO3 conversion efficiency can be calculated by dividing the amount of SO3 produced in the reaction by the theoretical maximum amount of SO3 that could be produced from the initial amount of SO2 present. This calculation gives a percentage that represents the efficiency of the conversion process.
What is the percent composition by mass of SO2?
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Which of the carbon monoxide sulfur dioxide nitrogen dioxide and ozone diffuse at the slowest rate?
According to Graham's Law, diffusion rate of a gas is inversely proportional to the square root of the molar mass of that gas. Put another way, the heavier the gas, the slower it will diffuse. CO is 28; SO2 is 64; NO2 is 46; O3 is 48. So the slowest to diffuse would be SO2.
How many moles of Carbon are needed to react with 0.540 mole SO2?
1.35
What gas is not produced by volcanic eruption?
One gas that is not produced by volcanic eruptions is carbon monoxide (CO). While volcanoes commonly emit gases like carbon dioxide (CO2), sulfur dioxide (SO2), and water vapor (H2O), carbon monoxide is typically associated with combustion processes rather than volcanic activity. Volcanic gases primarily result from the melting of magma and the release of dissolved gases, which do not include carbon monoxide as a significant output.
Which is the greatest mass of SO2 that can produced from 15.0 mol Cu2S?
To find the maximum mass of SO2 produced from 15.0 mol of Cu2S, first determine the molar ratio between Cu2S and SO2. The balanced chemical equation shows that 4 mol of SO2 is produced for every 1 mol of Cu2S consumed. Thus, you would produce 60.0 mol of SO2 from 15.0 mol of Cu2S. Finally, convert the moles of SO2 to grams using the molar mass of SO2 to find the mass.
What mass of so2 is produced from the reaction of 31.5g of s8 and 8.65g of o2?
First, balance the chemical equation: S8 + 8 O2 -> 8 SO2. Calculate the moles of each reactant using their molar masses. The limiting reactant is the one that produces the least amount of SO2, which is S8 in this case. Therefore, use the stoichiometry of the balanced equation to calculate the mass of SO2 produced from 31.5g of S8.
What is the mass of 0.75 mole of so2?
The molar mass of SO2 (sulfur dioxide) is approximately 64.06 g/mol. To find the mass of 0.75 moles of SO2, you would multiply the number of moles (0.75) by the molar mass (64.06 g/mol) to get the mass of 0.75 moles of SO2, which is 48.045 grams.
What is the total mass and grams of 0.75 mole of SO2?
The molar mass of SO2 is approximately 64.07 g/mol. To find the mass of 0.75 moles of SO2, you would multiply the number of moles by the molar mass: 0.75 moles x 64.07 g/mol = 48.05 grams Therefore, the total mass of 0.75 moles of SO2 is 48.05 grams.
What is the total mass of 0.75 mol of SO2?
The molar mass of sulfur dioxide (SO2) is approximately 64.07 g/mol. Therefore, the total mass of 0.75 mol of SO2 would be 0.75 mol * 64.07 g/mol = 48.05 grams.
What is the mass percent of oxygen (O) in SO2?
(16.0g + 16.0g)/(32.1g + 16.0g + 16.0g) x 100 %
Is SO2 an organic molecule?
There is no carbon atoms.So SO2 is inorganic.
What is the mass percent of oxygen in SO2?
The molar mass of SO2 is 64.07 g/mol. Since oxygen has a molar mass of 16 g/mol and there are 2 oxygen atoms in SO2, the total mass of oxygen in SO2 is 32 g. Therefore, the mass percent of oxygen in SO2 is 32/64.07 * 100% = 50.05%.
How many moles in 37.4g of SO2?
The formula mass of the compound sulfur dioxide, SO2 is 32.1 + 2(16.0) = 64.1Amount of SO2 = mass of pure sample/molar mass = 37.4/64.1 = 0.583mol There are 0.583 moles of sulfur dioxide in a 37.4g pure sample.
How many moles of SO2 is present in 0.45 grams of sulfur dioxide?
To determine the number of moles of SO2 in 0.45 grams of sulfur dioxide, you need to use the molar mass of SO2. The molar mass of SO2 is about 64.06 g/mol. Divide the given mass by the molar mass to find the number of moles. In this case, 0.45 grams divided by 64.06 g/mol gives you approximately 0.007 moles of SO2.
What is the mass percent of oxygen on SO2?
The molar mass of SO2 is 64.07 g/mol. Oxygen has a molar mass of 16.00 g/mol. To calculate the mass percent of oxygen in SO2, we can divide the molar mass of oxygen (32.00 g) by the molar mass of SO2 (64.07 g) and multiply by 100 to get 50.05%.
What is the total mass in grams of 0.75 mole of SO2?
To find the total mass of 0.75 moles of SO2, you need to calculate the molar mass of SO2 and then multiply it by the number of moles. The molar mass of SO2 is approximately 64.06 g/mol. Therefore, the total mass of 0.75 moles of SO2 is 0.75 mol * 64.06 g/mol = 48.045 grams.
