Ba2+(aq) + SO42-(aq) --> BaSO4(s)
The other ions, Cu2+ and Cl-, don't react (tribune ions).
Copper (II) sulphate, CuSO4 is prepared by mixing copper (II) oxide, CuO with sulfuric acid, H2SO4. CuO + H2SO4 --> CuSO4 + H2O
The precipitate is copper(II) hydroxide. The chemical reaction is:2 NaOH + CuSO4 = Cu(OH)2 + Na2SO4
Yes, white CuSO4 can absorb 1 to 5 molecules of H2O (mono- and penta-hydrates (blue) are formed).
Assuming you mean a reaction between potassium (K) and copper(II) sulfate, your products would be potassium sulfate and copper in a single replacement reaction. Here's the equation:2K + CuSO4 --> K2SO4 + Cu
CuSO4 · 5H2O has 5 water molecules attached to each CuSO4 molecule.
CuSO4(aq) + BaCl2(aq) -> CuCl2(aq) + BaSO4(s)
The chemical equation for the reaction between barium chloride (BaCl2) and copper sulfate (CuSO4) is: BaCl2 + CuSO4 -> BaSO4 + CuCl2. This reaction forms barium sulfate (BaSO4) and copper (II) chloride (CuCl2) as the products.
BaCl2 + CuSO4 = BaSO4 = CuCl2
The insoluble product of the reaction between KOH and CuSO4 is copper(II) hydroxide (Cu(OH)2). This can be found by determining the products formed from the reaction between the potassium hydroxide (KOH) and copper sulfate (CuSO4), and then identifying the insoluble compound formed, which is copper(II) hydroxide.
The molecular equation for the reaction between copper (II) sulfate and barium chloride is: CuSO4 + BaCl2 -> BaSO4 + CuCl2. In this reaction, the copper (II) ions switch places with the barium ions to form barium sulfate and copper (II) chloride.
These substances doesn't react.
When copper sulfate (CuSO4) reacts with hydrochloric acid (HCl), copper chloride (CuCl2) and sulfuric acid (H2SO4) are formed as products. The balanced chemical equation for this reaction is CuSO4 + 2HCl -> CuCl2 + H2SO4.
Copper (II) sulphate, CuSO4 is prepared by mixing copper (II) oxide, CuO with sulfuric acid, H2SO4. CuO + H2SO4 --> CuSO4 + H2O
The precipitate is copper(II) hydroxide. The chemical reaction is:2 NaOH + CuSO4 = Cu(OH)2 + Na2SO4
The ionic equation for barium chloride (BaCl2) plus copper sulfate (CuSO4) is Ba2+ + SO4^2- → BaSO4(s) and Cu2+ + 2Cl- → CuCl2. This suggests the formation of a white precipitate of barium sulfate and copper chloride in solution.
Yes, white CuSO4 can absorb 1 to 5 molecules of H2O (mono- and penta-hydrates (blue) are formed).
No, the equation for this reaction is: CuCO3(s) + H2SO4(aq) ---> CuSO4(aq) + CO2(g) + H2O(l) Therefore, the gas produced is carbon dioxide, this is produced in every reaction of a carbonate with an acid.