Carbon dioxide (CO^2)
The molar mass of glucose is 180,16 g.
To find the percent by mass of the solution, first calculate the total mass of the solution, which is the sum of the mass of glucose and the mass of water: 50.0 g (glucose) + 1000.0 g (water) = 1050.0 g. The percent by mass of glucose in the solution is then calculated as (mass of glucose / total mass of solution) × 100 = (50.0 g / 1050.0 g) × 100 ≈ 4.76%. Therefore, the percent by mass of glucose in the solution is approximately 4.76%.
To find the mass of 2.56 moles of glucose (C₆H₁₂O₆), first determine the molar mass of glucose. The molar mass is approximately 180.18 g/mol. Therefore, the mass of 2.56 moles of glucose can be calculated as follows: 2.56 moles × 180.18 g/mol = approximately 461.66 grams.
To determine the mass of the solution, we need to calculate the total mass of the solution when 81g of glucose is added. Since the solution is 15.0% glucose by mass, the remaining 85.0% is water. Therefore, the total mass of the solution can be calculated using the mass of glucose added and the percentage of water. This would result in a total mass of solution greater than 81g due to the addition of water to dissolve the glucose.
To find the percent of glucose in the solution, use the formula: [ \text{Percent of glucose} = \left( \frac{\text{mass of glucose}}{\text{mass of solution}} \right) \times 100 ] The mass of the solution is the sum of the mass of glucose and the mass of water: ( 4.6 , \text{g} + 145.2 , \text{g} = 149.8 , \text{g} ). Thus, [ \text{Percent of glucose} = \left( \frac{4.6}{149.8} \right) \times 100 \approx 3.07% ] So, the percent of glucose in the solution is approximately 3.07%.
The molar mass of glucose is 180,16 g.
Most of the mass of a tree comes from carbon dioxide in the air, which is converted into glucose through photosynthesis.
Most of the mass of a tree comes from carbon dioxide in the air, which is converted into glucose through photosynthesis.
The molar mass of glucose is 180.15588 g/mol.
The gram molecular mass of glucose is 180 gram. Reason. The atomicity of glucose is 24.
To find the percent by mass of the solution, first calculate the total mass of the solution, which is the sum of the mass of glucose and the mass of water: 50.0 g (glucose) + 1000.0 g (water) = 1050.0 g. The percent by mass of glucose in the solution is then calculated as (mass of glucose / total mass of solution) × 100 = (50.0 g / 1050.0 g) × 100 ≈ 4.76%. Therefore, the percent by mass of glucose in the solution is approximately 4.76%.
the nucleus
To find the molality of a solution, you need the mass of the solvent (usually water) in kilograms and the number of moles of solute (glucose). Given that the solution is 7.80% glucose by weight, you can calculate the mass of glucose in the solution and then convert it to moles using the molar mass of glucose. From there, you can find the molality by dividing the moles of glucose by the mass of the solvent in kilograms.
To find the mass of 2.56 moles of glucose (C₆H₁₂O₆), first determine the molar mass of glucose. The molar mass is approximately 180.18 g/mol. Therefore, the mass of 2.56 moles of glucose can be calculated as follows: 2.56 moles × 180.18 g/mol = approximately 461.66 grams.
To determine the mass of the solution, we need to calculate the total mass of the solution when 81g of glucose is added. Since the solution is 15.0% glucose by mass, the remaining 85.0% is water. Therefore, the total mass of the solution can be calculated using the mass of glucose added and the percentage of water. This would result in a total mass of solution greater than 81g due to the addition of water to dissolve the glucose.
To find the percent of glucose in the solution, use the formula: [ \text{Percent of glucose} = \left( \frac{\text{mass of glucose}}{\text{mass of solution}} \right) \times 100 ] The mass of the solution is the sum of the mass of glucose and the mass of water: ( 4.6 , \text{g} + 145.2 , \text{g} = 149.8 , \text{g} ). Thus, [ \text{Percent of glucose} = \left( \frac{4.6}{149.8} \right) \times 100 \approx 3.07% ] So, the percent of glucose in the solution is approximately 3.07%.
The mass of the glucose solution can be calculated using the formula: mass = density x volume. In this case, mass = 1.15 g/mL x 0.750 L = 0.8625 g. So, the mass of the glucose solution that fills the 0.750 L intravenous bottle is 0.8625 grams.