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Assuming the wire follows Ohm's Law, the resistance of a wire is directly proportional to its length therefore doubling the length will double the resistance of the wire. However when the length of the wire is doubled, its cross-sectional area is halved. ( I'm assuming the volume of the wire remains constant and of course that the wire is a cylinder.) As resistance is inversely proportional to the cross-sectional area, halving the area leads to doubling the resistance. The combined effect of doubling the length and halving the cross-sectional area is that the original resistance of the wire has been quadrupled.
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Why the wires in the resistance box are double folded?
The wires in the resistance box are double folded to reduce their resistance value by a factor of 4, as resistance is inversely proportional to the cross-sectional area of the wire. This allows for more precise resistance increments to be achieved by varying the length of wire exposed in the circuit.
What is the relationship between wire size length of run and voltage drop?
The wire resistance is proportional to the length of wire divided by its cross-section area. The voltage drop is proportional to the resistance times the current.
How does increasing the wire gauge from awg 22 to awg 26 generally effect resistance?
Increasing the wire gauge from AWG 22 to AWG 26 will increase the wire's resistance because a higher gauge corresponds to a thinner wire. Thinner wires have higher resistance due to increased electrical resistance per unit length. Therefore, a wire with AWG 26 will have higher resistance compared to a wire with AWG 22.
Electric current flows in a wire which is opposed by what?
Electric current flowing in a wire is opposed by electrical resistance. This resistance is caused by factors such as the material of the wire, its length, and its cross-sectional area. It results in the conversion of electrical energy into heat.
Why the resistance is directly proportion to the lenght of a conductor?
Resistance is caused due to the collision of the moving free electrons in a conductor with the fixed positive ions in the metal when a potential difference is applied across the conductor. As the length increases, the number of collisions by the moving free electrons with the fixed positive ions increases as more number of fixed positive ions are present in an increased length of the conductor. As a result, resistance increases. -Sanjay
A 4 ohm resistance wire is doubled on it calculate the new resistance of the wire?
The resistance of a wire is directly proportional to its length, so doubling the length will also double the resistance. Therefore, doubling the 4 ohm resistance wire will result in a new resistance of 8 ohms.
What is the Change in resistance of wire when its length is double?
Assuming the wire follows Ohm's Law, the resistance of a wire is directly proportional to its length therefore doubling the length will double the resistance of the wire. However when the length of the wire is doubled, its cross-sectional area is halved. ( I'm assuming the volume of the wire remains constant and of course that the wire is a cylinder.) As resistance is inversely proportional to the cross-sectional area, halving the area leads to doubling the resistance. The combined effect of doubling the length and halving the cross-sectional area is that the original resistance of the wire has been quadrupled.
How Does the length of the wire affect its resistance?
As the length of the wire increases, the resistance also increases. This is because a longer wire offers more opposition to the flow of electrical current compared to a shorter wire. Resistance is directly proportional to length, so doubling the length of the wire will double its resistance.
Which is a better conductor between a short wire and long wire?
Double the length is double the resistance. Resistance of a wire is the resistivity of the material, times the length, divided by the cross-section area.
What will happen to the current if double the length of the wire?
If you double the length of the wire while keeping the resistance constant, the current will halve because resistance is directly proportional to the length of the wire. This is described by Ohm's law (V = I * R), where V is voltage, I is current, and R is resistance.
What will happen to the resistance of a wire if it is stretched to increase its length by 2 times?
Actually resistance is directly proportional to the length provided area remains constant. But as we stretch the wire only its volume would remain constant. So its area is to be decreased as length increases. V = pi r^2 * L Now we have R = K * L / pi r^2 Multiplying numerator and denominator by L we get R = K/V * L^2 So resistance is found to be proportional to square of length Hence as length gets increased by 2 times, its resistance value would increase by 4 times.
What is the Change in resistivity of wire when its resistivity is doubled?
Resistivity of a wire of a certain material is independent of the wire's length. The only thing that would change is resistance. Since R=ρ/A, in the case of length doubling, resistance will also double.Resistance (R, Ω)Resistivity (ρ, Ω m)Length (, m)Cross surface area (A, m²)
If the length of a copper wire is reduced by half then the resistance of the wire will be?
The resistance of a wire is directly proportional to its length, so if the length is reduced by half, the resistance will also be reduced by half.
How does the resistance of a wire vary with its length?
The resistance of a wire is directly proportional to its length. This means that as the length of the wire increases, the resistance also increases. This relationship is described by the formula R = ρ * (L/A), where R is resistance, ρ is the resistivity of the material, L is the length of the wire, and A is its cross-sectional area.
What is one thing that you could do to the wire used in a circuit to decrease the amount of resistance bulb by the wire?
Use thicker wire. Doubling the diameter gives one quarter the resistance.
Why the wires in the resistance box are double folded?
The wires in the resistance box are double folded to reduce their resistance value by a factor of 4, as resistance is inversely proportional to the cross-sectional area of the wire. This allows for more precise resistance increments to be achieved by varying the length of wire exposed in the circuit.
How does the length of a wire affect the resistance?
Yes, resistance is directly proportional to the length, and inversely proportional to the cross sectional area. R = p*l/A. Where R is the resistance of the piece of conducting material, p is Greek letter rho, representing the resistivity of the material, l (lower case L) is the length, and A is the area.
