answersLogoWhite

0

Because there are so many, many, many parts in it. 12 in one dozen, 144 in one gross, 6*10^23 in one mole. This is all by definition or concensis, something like: how many players are in a football team.

User Avatar

Wiki User

8y ago

What else can I help you with?

Related Questions

What is the number of atoms of nitrogen of .755 mol of N2?

There are 9.06 x 10^22 atoms of nitrogen in 0.755 mol of N2. This is calculated by multiplying Avogadro's number (6.022 x 10^23) by the number of moles of N2 (.755 mol) and the number of nitrogen atoms in one molecule of N2 (2 atoms).


How many atoms are present in 80.0 mol of zirconium?

To determine the number of atoms in 80.0 mol of zirconium, you can use Avogadro's number, which is 6.022 x 10^23 atoms/mol. Multiply 80.0 mol by Avogadro's number to find the total number of atoms in 80.0 mol of zirconium.


How many atoms are in 7.1 mol Zn?

From my understanding as there is only one mole of zinc which means the mass is 65.4 . Then to get the number of particles the answer is simply 1(the number of moles) x 6.02 x 10 ^ 23. is this correct this is not the answer just a further question ...


The number of grams in 2.65 mol of So2 is 2.65?

To find the number of grams in 2.65 mol of SO2, you need to multiply the molar mass of SO2 by the number of moles given. The molar mass of SO2 is approximately 64.07 g/mol. So, 2.65 mol of SO2 would be equivalent to 2.65 mol * 64.07 g/mol = 169.48 g.


What is the answer. Determine the number of atoms in 3.29 mol Zn?

To determine the number of atoms in 3.29 mol of Zn, you would use Avogadro's number, which is 6.022 x 10^23 atoms/mol. Multiply the number of moles (3.29 mol) by Avogadro's number to find the number of atoms. The calculation would be: 3.29 mol Zn x 6.022 x 10^23 atoms/mol = 1.98 x 10^24 atoms of Zn.


How many particles are present in 1 mol of a pure substance?

One mol of a pure substance contains 6.0221367 x 10^23 particles according to Avogadro's number.


Calculate the number of hydroxide ions present in 0.250 mol of Ca(OH)2?

Since there are 2 hydroxide ions (OH-) for every one molecule of Ca(OH)2, in 0.250 mol of Ca(OH)2 there are 0.500 mol of hydroxide ions. We can then multiply 0.500 mol by Avogadro's number to find the number of hydroxide ions present, which is approximately 3.01 x 10^23 ions.


How many particles are in 8.00 mol?

There are approximately 4.81 x 10^24 particles in 8.00 mol. This is calculated by multiplying Avogadro's number (6.022 x 10^23 particles/mol) by the number of moles given (8.00 mol).


How do you find the number of atoms in 6.21 mol of Mg?

To find the number of atoms in 6.21 mol of Mg, you would use Avogadro's number, which is 6.022 x 10^23 atoms/mol. So, for 6.21 mol of Mg, you would multiply the number of moles by Avogadro's number to get the number of atoms.


How many atoms are there in 1 mol of an element?

There are approximately 6.022 x 10^23 atoms in 1 mol of an element, which is known as Avogadro's number. This number is a constant and represents the number of atoms, ions, or molecules in one mole of a substance.


Calculate the number of atom in 13.2 mol copper?

To calculate the number of atoms in 13.2 mol of copper, you can use Avogadro's number, which is approximately 6.022 x 10^23 atoms per mole. Multiply 13.2 mol by Avogadro's number to get the number of atoms: 13.2 mol * (6.022 x 10^23 atoms/mol) = 7.93 x 10^24 atoms. Therefore, there are approximately 7.93 x 10^24 atoms in 13.2 mol of copper.


What contains the greatest number of molecules out of 0.5 mol CaNO32 or 2.3 mol H2O or 1.2 mol H2O2?

The answer is 2,3 moles water.