9.8 meters (32.2 feet) per second2 downward.
The force of the rifle on the bullet and the force of the bullet on the rifle are equal in magnitude but opposite in direction, according to Newton's third law of motion. However, the mass of the rifle is much larger than the mass of the bullet, so the acceleration of the rifle is much smaller compared to the acceleration of the bullet.
Both objects accelerate, however due to Newton's 2nd law the acceleration of the rifle is less due to it's higher mass. Newton's second law F = ma In your question the force (F) would be the same on both objects, but the mass (m) would be different and give a different answer for acceleration (a). This difference can be seen by looking at the effect of being on opposite sides of the rifle (ie kickback vs bullet hole)
No, this statement is not true. When a rifle is fired horizontally, the bullet immediately begins to drop due to gravity as soon as it leaves the barrel. The rate of drop will depend on the muzzle velocity of the bullet and the distance it has traveled.
The force of the rifle returning back after firing a bullet is smaller than the force on the bullet because the rifle has a larger mass compared to the bullet. According to Newton's third law, force is equal to mass times acceleration, so the force exerted on the rifle is smaller due to the larger mass and slower acceleration compared to the bullet.
They hit at almost exactly the same time. Just because the bullet from the gun is moving horizontally at high speed, this does not mean it escapes the pull of gravity. However, the direction of the fired bullet is "horizontal" (perpendicular to the vertical pull of gravity). This vector is very slightly tangential to the force of gravity, because the Earth is curved. So although the bullet path describes an arc, it is very, very slightly above the curvature of the Earth. The difference for this case would be practically immeasurable. However, for faster projectiles it would be proportionally larger.
The force of the rifle on the bullet and the force of the bullet on the rifle are equal in magnitude but opposite in direction, according to Newton's third law of motion. However, the mass of the rifle is much larger than the mass of the bullet, so the acceleration of the rifle is much smaller compared to the acceleration of the bullet.
Both objects accelerate, however due to Newton's 2nd law the acceleration of the rifle is less due to it's higher mass. Newton's second law F = ma In your question the force (F) would be the same on both objects, but the mass (m) would be different and give a different answer for acceleration (a). This difference can be seen by looking at the effect of being on opposite sides of the rifle (ie kickback vs bullet hole)
No, this statement is not true. When a rifle is fired horizontally, the bullet immediately begins to drop due to gravity as soon as it leaves the barrel. The rate of drop will depend on the muzzle velocity of the bullet and the distance it has traveled.
The force of the rifle returning back after firing a bullet is smaller than the force on the bullet because the rifle has a larger mass compared to the bullet. According to Newton's third law, force is equal to mass times acceleration, so the force exerted on the rifle is smaller due to the larger mass and slower acceleration compared to the bullet.
They hit at almost exactly the same time. Just because the bullet from the gun is moving horizontally at high speed, this does not mean it escapes the pull of gravity. However, the direction of the fired bullet is "horizontal" (perpendicular to the vertical pull of gravity). This vector is very slightly tangential to the force of gravity, because the Earth is curved. So although the bullet path describes an arc, it is very, very slightly above the curvature of the Earth. The difference for this case would be practically immeasurable. However, for faster projectiles it would be proportionally larger.
Both bullets would hit the ground at the same time, regardless of their initial velocities. This is due to the fact that in the absence of air resistance, the only force acting on the bullets is gravity, which causes all objects to fall at the same rate regardless of their mass or initial velocity.
The acceleration of the bullet is greater than the acceleration of the rifle because the bullet has a much smaller mass. Newton's second law, F=ma, states that the acceleration is inversely proportional to mass given the same force, so the smaller mass of the bullet results in a greater acceleration for the same force applied.
As soon as it leaves the muzzle of the rifle. To hit a target at any distance, the line of sight of the barrel will be tilted so that it is ABOVE horizontal- and gravity will cause the bullet to curve back to earth- or your target.
One. Only the bullet's weight. In this case, the bullet would not decelerate and will keep moving at muzzle velocity until it hits the ground.
Yes, when a bullet is fired from a rifle, the bullet typically has greater momentum and kinetic energy compared to the rifle. This is due to the bullet's higher velocity and lower mass compared to the rifle.
Rifle and bullet (The bullet is dependent on the rifle to accomplish its purpose)
Using Newton's second law (F=ma), the acceleration of the bullet can be calculated by dividing the force by the mass of the bullet. First, convert the mass of the bullet to kg (7.0g = 0.007kg), then divide the force (2.1N) by the mass (0.007kg) to find the acceleration. The acceleration of the bullet would be 300 m/s^2.