answersLogoWhite

0

Molar mass of an element is the atomic weight on the Periodic Table in grams. 1 mole of atoms of an element is 6.022 x 1023 atoms. To find the mass of one atom of an element, divide the element's molar mass by 6.022 x 1023 atoms.

Example:

Sodium, Na, has a molar mass of 22.989770g/mol (atomic weight in grams)

1 mole Na atoms = 6.022 x 1023 atoms

Solution:

22.989770g/mol x 1mol/6.022 x 1023 atoms = 3.818 x 10-23g/atom

User Avatar

Wiki User

12y ago

What else can I help you with?

Continue Learning about Physics

How many moles are in 42 grams of CO2?

To calculate the number of moles in 42 grams of CO2, we first need to find the molar mass of CO2, which is approximately 44 grams per mole. Then, divide the given mass by the molar mass to find the number of moles. In this case, 42 grams of CO2 is equivalent to 42/44 = 0.955 moles.


What is a mass-mass problem?

A mass-mass problem is a kind of problem wherein a person is asked to find an answer which is also a mass. In this, a person is given mass of a compound and then asked to find the mass of another compound.


What is the total number of moles present in a 52.0 gram sample of NaN3 gram formula mass equals 65.0 mole?

To calculate the total number of moles in the 52.0 gram sample of NaN3, divide the given mass by the molar mass of NaN3. First, determine the molar mass of NaN3 by summing the atomic masses of its elements (sodium, nitrogen, and three times the atomic mass of nitrogen). Then, divide the mass of the sample by the molar mass of NaN3 to find the number of moles.


What number of moles of O2 is needed to produce 142 grams of P4O10 from P?

We first calculate the molar mass of P4O10, which is 284 g/mol. Then we convert the given mass of P4O10 (142 g) to moles using its molar mass. There is a 1:4 molar ratio between P4O10 and O2 in the reaction, so we multiply the moles of P4O10 by 4 to find the moles of O2 needed.


How do you find 1.1 grams of feci3 In moles?

To find the number of moles in 1.1 grams of FeCl3, you'll first determine the molar mass of FeCl3 (55.85 + 35.45*3) = 162.31 g/mol. Then, divide the given mass (1.1g) by the molar mass to get the number of moles (1.1g / 162.31g/mol ≈ 0.007 moles of FeCl3).

Related Questions

How do you find the molar mass of an atom?

To find the molar mass of an atom, you need to add up the atomic masses of all the atoms in its chemical formula. This can be determined from the periodic table. The unit for molar mass is grams per mole.


How do you find moles of hydrogen?

To find the moles of hydrogen, you can divide the given mass of hydrogen by its molar mass. The molar mass of hydrogen is approximately 1 g/mol. So, moles of hydrogen = mass of hydrogen (in grams) / molar mass of hydrogen (approximately 1 g/mol).


How many moles of atom is contained in 15 gram of zinc?

To find the number of moles of zinc in 15 grams, divide the given mass by the molar mass of zinc. The molar mass of zinc is approximately 65.38 g/mol. Therefore, 15 grams of zinc is equal to 0.23 moles of zinc.


How is the number of moles of an element determined from the known mass?

To determine the number of moles of an element from its known mass, you can use the formula: moles = mass / molar mass. First, find the molar mass of the element from the periodic table. Then, divide the given mass of the element by its molar mass to find the number of moles.


What is the molar mass of the nonelectrolyte compound if a 4.305 g sample of it is dissolved in 105 g of water?

To find the molar mass of the nonelectrolyte compound, we need to use the formula: Molar mass (mass of compound / moles of compound) First, we need to find the moles of the compound by using the formula: moles mass / molar mass Given that the mass of the compound is 4.305 g and it is dissolved in 105 g of water, we can calculate the moles of the compound. Next, we can find the molar mass of the compound by rearranging the formula: Molar mass mass / moles By plugging in the values, we can calculate the molar mass of the nonelectrolyte compound.


What is molar mass of iron?

The molar mass of iron is 55.845g per mol. Molar mass is the mass of a given substance divided by its amount of substance.


Convert grams to moles?

To convert grams to moles, you need to know the molar mass of the substance. Divide the given mass in grams by the molar mass to find the number of moles. This calculation is done using the formula: moles = grams / molar mass.


What is the percent composition by mass of phosphorous in ammonium phosphate?

Ammonium phosphate ((NH4)3PO4) contains one phosphorus atom in the formula. To calculate the percent composition by mass of phosphorus, you need to find the molar mass of phosphorus and the molar mass of the entire compound. Then, divide the molar mass of phosphorus by the molar mass of the compound and multiply by 100 to get the percentage.


30.4 grams of X2O3 gas makes 2 atm pressure at 273 C in a 8.96 liter container. So, howmany g.mol is the molar mass of the X atom of the X atom (O:16)?

To find the molar mass of X, we need to calculate the number of moles of X2O3 gas present in the container using the ideal gas law. Once we have the number of moles, we can calculate the molar mass of X by dividing the mass of X in the given amount of X2O3 by the number of moles. This will give us the molar mass of X in grams per mole.


What do you mean by molar mass of an element?

Molar mass is defined as the mass of 6.022x1023 atoms/molecules of a given substance.


If given number of moles volume density and molar volume how do you find the molar mass?

Molar mass is the sum of all of its elements' average atomic mass in grams. Such as: NH4 would be calculated by adding nitrogen's aam (14.007) and hydrogen's aam multiplied by four (1.0079 x 4 = 4.0316). Therefore, ammonium's molar mass would be (14.007+4.0316) 18.039. Rounded to sig figs.


What is the percentage composition of molar mass in the given compound?

The percentage composition of molar mass in a compound is the percentage of each element's mass contribution to the total molar mass of the compound.