I is a straight line originating from a certain y=intercept and then intercept x-axis and ends on the same initial value of velocity but this time it is negative.
When the ball leaves your hand (that is when you throw it up) it already has some velocity, this is where the line intercepts y-axis at whatever the value of velocity is. As it goes up till its height the velocity is zero here it cuts the x-axis at whatever time the ball is at it's peak. Then when the ball comes down the velocity is opposite to the previous one thus it will be negative bow and moves down the x-axis and ends where the initial till the initial value of velocity because of law of conservation of energy.
The speed of a ball thrown upward upon striking the ground will be the same as the speed at which it was thrown, but in the opposite direction. The speed of a ball thrown downward upon striking the ground will be faster than the speed at which it was thrown due to the acceleration from gravity.
The acceleration of a ball at the top of its trajectory when thrown straight upward is equal to the acceleration due to gravity, which is approximately 9.81 m/s^2 downward. At the top of its trajectory, the ball momentarily comes to a stop before reversing direction and accelerating downward.
The acceleration of the object would still be g downward, regardless of the angle at which it is thrown upward. The acceleration due to gravity always acts in the downward direction towards the center of the Earth. The only difference would be the horizontal component of the velocity due to the initial angle of the throw.
At the top of its flight, the acceleration of the rock must be equal to the acceleration due to gravity acting downward. This acceleration is approximately 9.8 m/s^2 on Earth.
The acceleration of the ball just before it hits the ground is equal to the acceleration due to gravity, which is approximately 9.81 m/s^2 downward.
The speed of a ball thrown upward upon striking the ground will be the same as the speed at which it was thrown, but in the opposite direction. The speed of a ball thrown downward upon striking the ground will be faster than the speed at which it was thrown due to the acceleration from gravity.
The acceleration of a ball at the top of its trajectory when thrown straight upward is equal to the acceleration due to gravity, which is approximately 9.81 m/s^2 downward. At the top of its trajectory, the ball momentarily comes to a stop before reversing direction and accelerating downward.
The acceleration of the object would still be g downward, regardless of the angle at which it is thrown upward. The acceleration due to gravity always acts in the downward direction towards the center of the Earth. The only difference would be the horizontal component of the velocity due to the initial angle of the throw.
If it is gravitational acceleration then it it is positive in downward and negative in upward direction..if it is not gravitational acceleration then it is depending upon the value of acceleration.
At the top of its flight, the acceleration of the rock must be equal to the acceleration due to gravity acting downward. This acceleration is approximately 9.8 m/s^2 on Earth.
The acceleration of the ball just before it hits the ground is equal to the acceleration due to gravity, which is approximately 9.81 m/s^2 downward.
When a ball is thrown upward, it experiences a brief period of acceleration while moving against the force of gravity. Once the ball reaches its peak height, it begins to fall back down due to gravity.
The speed of the body at the highest point is 0 m/s. The acceleration acting on the body is the acceleration due to gravity (-9.81 m/s^2), which acts downward throughout the motion.
The thrown ball will (usually) have the highest velocity as the acceleration (resultant of force) used to throw it exceeds that of the other two balls. The ball thrown upward will have a higher downward velocity than the dropped ball even though their accelerations (due to gravity) are the same, as it has more time to travel downward. Although, If the ball thrown upward is thrown high enough, it may even travel faster than the ball thrown downward if the downward throw's force is not enough to beat the ball's terminal velocity (quite a bit of height would be required though).
From the time the object leaves your hand, its acceleration doesn't change at all ... it remains constant at 9.8 meters (32.2 feet) per second2 downward. Well, we have to admit that the acceleration does change to zero once the object hits the ground.
No, the acceleration at the highest point is never 0.
When an object is thrown upward, the acceleration due to gravity acts downward while the velocity is directed upward. This leads to a decrease in the speed of the object until it reaches its highest point and changes direction.