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Five. An amp (C/S) is a measure of Coulombs (C) per second (S). A coulomb is a quantity of electrons, so you can think of this as the # of electrons passing a point on a wire, like the flow of a river measured in gallons per second. A volt (J/C) is the amount of energy, measured in Joules (J), per Coulomb. Finally, a Watt (W = J/S) is the measure of energy (J) per second (S). That's why a higher wattage bulb is brighter and hotter... it's using more energy.

Therefore, Amps = W / V = (J/S) / (J/C) = (J/S) * (C/J) = C/S = 60/12 = 5

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How do you work out how many amps a forty watt bulb uses?

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