Five. An amp (C/S) is a measure of Coulombs (C) per second (S). A coulomb is a quantity of electrons, so you can think of this as the # of electrons passing a point on a wire, like the flow of a river measured in gallons per second. A volt (J/C) is the amount of energy, measured in Joules (J), per Coulomb. Finally, a Watt (W = J/S) is the measure of energy (J) per second (S). That's why a higher wattage bulb is brighter and hotter... it's using more energy.
Therefore, Amps = W / V = (J/S) / (J/C) = (J/S) * (C/J) = C/S = 60/12 = 5
A 60 watt light bulb typically draws 0.5 amps from a 120-volt power source. This is calculated by dividing the wattage (60 watts) by the voltage (120 volts).
If a light bulb is rated at 60 Watts, the voltage will depend on the specific type of bulb. For a typical incandescent bulb, the voltage would be around 120 volts. However, for an LED or CFL bulb, the voltage could be different, such as 120 volts or 240 volts.
What you are asking is kinda like asking how many oranges in an apple.Voltage is the measure of electrical potential.Amperage is the measure of electrical flow quantity.A good illustration is a water pipe: you can have high pressure (volts) but unless the water is allowed to flow the quantity of water is zero. (amps)
Each light bulb will receive the full 9 volts from the battery in a series circuit, so each bulb will be operating on 9 volts.
A 1 horsepower motor typically draws around 10 amps at 120 volts and 5 amps at 240 volts. The actual amperage can vary depending on the efficiency and design of the motor.
amps equals watts divided by volts.
To calculate the amperage of a 40-watt bulb, you need to use the formula: Amps = Watts / Volts. If the bulb operates at 120 volts (standard for US households), the amperage will be 0.33 amps (40 watts / 120 volts).
The amps drawn by a 65 watt light bulb should be 65/120 or 0.54167. This fraction of an ampere may be restated as 541.67 milli-amps.
Watts = Volts X Amps. Amps=Watt / Volts. So, with a 240V mains, a 60W bulb draws 0.25amps. On a 12 system (car/auto) a 60W bulb draws 5 amps. On a 110V mains, a 60W bulb draws .55 Amps.
Amps x volts = watts So, assuming you are running on 110 volt line, the answer is 65 watts/110 volts=.591 amps.
Watts = Volts x Amps x Power Factor. An incandescent light bulb is a resistive load so PF = 1. ANSWER: = 1/2 Amp
The formula is volts times amps equals watts, or watts divided by volts equals amps.
You want to know how many amps in that circuit. To do so, divide the Watts by the Volts. in your case it would be 60 watts / 120 volts = 0.5 Amps.
If you divide the watts of the bulb by the supply voltage, that is the current. For example a 60 w bulb on a 240 v supply gives a current of 60/240 which is ¼ amp.
To find the current in amps for a 50-watt light bulb, you can use the formula ( I = \frac{P}{V} ), where ( I ) is the current in amps, ( P ) is the power in watts, and ( V ) is the voltage in volts. For example, if the bulb operates at 120 volts, the current would be ( \frac{50}{120} ), which equals approximately 0.42 amps. If the bulb operates at a different voltage, simply adjust the voltage in the formula accordingly.
To answer this question the voltage of the bulb is needed.
160 amps at 12v.