One needs to know the specific heat of concrete in order to answer this.
q = mC∆T
we know q = 52800 joules and the ∆T is 5 degrees. We do not know m (mass) or C (specific heat), so there are 2 unknowns.
The specific heat capacity of water is 4.186 J/g°C. Since there are 1000 grams in a kilogram, it would require 20,930 Joules of energy to increase the temperature of a kilogram of water by 5 degrees Celsius.
The specific heat capacity of water is 4.18 Joules/gram degrees Celsius. Therefore, it would take 4.18 Joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
The specific heat capacity of lead is 0.128 J/g°C. To calculate the heat energy needed to raise the temperature of the lead by 250°C, you would use the formula: Q = m x c x ΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature. Plugging in the values, the heat energy needed would be 6400 Joules.
To calculate the energy needed to change ice at -32.9 degrees to water at 75 degrees, you need to consider the energy required for three steps: Heating ice from -32.9 degrees to 0 degrees (specific heat capacity of ice) Melting ice at 0 degrees into water at 0 degrees (latent heat of fusion of ice) Heating water from 0 degrees to 75 degrees (specific heat capacity of water) Once you have the energy needed for each step, you can add them together to find the total energy required.
The amount of energy needed to raise the temperature of a substance is given by the equation Q = mcΔT, where Q is the energy, m is the mass, c is the specific heat capacity, and ΔT is the temperature change. For water, the specific heat capacity is 4.18 J/g°C. Plugging the values into the equation, we get Q = (2.0 g)(4.18 J/g°C)(5°C) = 41.8 J. Therefore, 41.8 Joules of energy is needed.
The specific heat capacity of water is 4.186 J/g°C. Since there are 1000 grams in a kilogram, it would require 20,930 Joules of energy to increase the temperature of a kilogram of water by 5 degrees Celsius.
True. A calorie is defined as the amount of heat energy needed to raise the temperature of 1 gram of water by 1 degree Celsius.
The specific heat capacity of water is 4.18 Joules/gram degrees Celsius. Therefore, it would take 4.18 Joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
1 calorie increases 1 gram of water by 1 degree celsius. 4.18 Joules are needed to increase the temperature of 1 gram of water by 1 degree celsius. To reduce the 1 gram of water 1 degree celsius it would have to give off 1 calorie of energy. To calculate the energy multiply the mass in grams of water by 4.18 and by the change in temperature. The energy = 4.18 x m x change in T. The answer is in Joules. If you are using calorie as the unit of energy, replace 4.18 J by 1 C. Note that food is measured in kilocalories (Calories) not metric calories.
The specific heat capacity of lead is 0.128 J/g°C. To calculate the heat energy needed to raise the temperature of the lead by 250°C, you would use the formula: Q = m x c x ΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature. Plugging in the values, the heat energy needed would be 6400 Joules.
2288777744x10 to the power of Bush
To calculate the energy needed to change ice at -32.9 degrees to water at 75 degrees, you need to consider the energy required for three steps: Heating ice from -32.9 degrees to 0 degrees (specific heat capacity of ice) Melting ice at 0 degrees into water at 0 degrees (latent heat of fusion of ice) Heating water from 0 degrees to 75 degrees (specific heat capacity of water) Once you have the energy needed for each step, you can add them together to find the total energy required.
As soon as the temperature drops below the dew point, water will condense from water vapor.
A room temperature ubove 0 degrees centigrade.
Specific heat capacity tells you how much stuff energy can store. specific heat capacity is the amount of energy needed to raise the temperature of 1kg of a substance by 1 degrees celsius. water has a specific heat capacity of 4200 J/kg degrees celsius.
The amount of energy needed to raise the temperature of a substance is given by the equation Q = mcΔT, where Q is the energy, m is the mass, c is the specific heat capacity, and ΔT is the temperature change. For water, the specific heat capacity is 4.18 J/g°C. Plugging the values into the equation, we get Q = (2.0 g)(4.18 J/g°C)(5°C) = 41.8 J. Therefore, 41.8 Joules of energy is needed.
You need the amount of water, the temperature of the water, and the desired temperature.