Someone that knows the answer pllz tell me i need the answer :(
no , it cannot be observed in same conditions of incident light because, the threshold energy will be different for different metals.so in that particular threshold energy only the photoelectric effect for that metal can be observed.....
All metals will emit a photoelectric effect. However, alkali metals do so in the visible light spectrum, while other metals do so in near-ultraviolet light.The alkali metals are: Lithium (Li), Sodium (Na), Potassium (K), Rubidium (Rb), Caesium (Cs), and Francium (Fr).
One of the most revolutionary concepts in physics is the photoelectric effect. The photoelectric effect occurs when radiant energy is impinged on various metals and electrons are ejected from the metal surface. The ejected photoelectrons have a certain kinetic energy which can be measured by the produced voltage. Photoelectric current cannot be explained by the wave theory as diffraction and interference can, however. The photoelectric effect is important because it revealed some of the limitations of the classical wave theory and it gave closer insight into the nature of light- namely the quantization as photons.
The reflectivity of metals changes with varying wavelengths. Generally, metals tend to reflect shorter wavelengths (such as blue light) more effectively than longer wavelengths (such as red light). This is due to the interaction between the metal's electrons and the incoming light waves.
Just visible light too can be used for photo electric phenomenon. But Hallwachs used UV rays as he used zinc plates. That is all. Moreover the energy of the photon has to be more than the work function of the material being used.
Alkali metals are used in the photoelectric effect because they have low ionization energies, making it easier for photons to eject electrons from their surface. This makes them efficient materials for producing a photoelectric effect. Additionally, alkali metals have a clean surface that allows for reliable and consistent results in experiments.
no , it cannot be observed in same conditions of incident light because, the threshold energy will be different for different metals.so in that particular threshold energy only the photoelectric effect for that metal can be observed.....
After irradiation with photons metals emit electrons.
All metals will emit a photoelectric effect. However, alkali metals do so in the visible light spectrum, while other metals do so in near-ultraviolet light.The alkali metals are: Lithium (Li), Sodium (Na), Potassium (K), Rubidium (Rb), Caesium (Cs), and Francium (Fr).
photoelectric effect
The ionization enthalpy of K and Cs is less than that of Li and therefore these metals easily lose electrons on exposure to light than lithium.That's the reason potassium and cesium are used in photoelectric cells rather than Cs.
potassium
There is the photoelectric effect, which is the process that emitts electrons from a metals surface when light of a certain frequency shines on the surface. In the metal, the nuclei are surrounded by electrons, so when the incoming electrons strike the surface, they pull apart from the electrons of the metal because of how like charges detract from each other.
One of the most revolutionary concepts in physics is the photoelectric effect. The photoelectric effect occurs when radiant energy is impinged on various metals and electrons are ejected from the metal surface. The ejected photoelectrons have a certain kinetic energy which can be measured by the produced voltage. Photoelectric current cannot be explained by the wave theory as diffraction and interference can, however. The photoelectric effect is important because it revealed some of the limitations of the classical wave theory and it gave closer insight into the nature of light- namely the quantization as photons.
reverse process of photo electric effect is done by the supply of electrons or heat to the metal that radiate certain radiation. among them the metals which emit visible radiation are normally used in house hold appliances
The photoelectric effect can be demonstrated using any metal. But for some ofthem, you might have to come up with a source of inconveniently-high-energyE&M radiation in order to demonstrate it.
The reflectivity of metals changes with varying wavelengths. Generally, metals tend to reflect shorter wavelengths (such as blue light) more effectively than longer wavelengths (such as red light). This is due to the interaction between the metal's electrons and the incoming light waves.