Devices, such as amplifiers can't be linear over all input values. At some point they just can't output the required output power. I.e. an amplifier that increases input power by a factor of 10, may not be able to amplify a signal that comes in that is, let's say 10 watts. The point where the device is outputing 1 dB less POWER (which is roughly running at 80%) than it should is the 1 dB compression point. So lets say a 10 watt signal is input, and that the signal should be amplified by a factor of 10, and should output 100 watts. Let's also say the system output power is actually 1 dB down from the expected value and outputting roughly 80 watts, 10 watts is the input 1 dB compression point. Also, look here: http://www.rfcafe.com/references/electrical/p1db.htm
The sound of Mach 1 is around 130 dB.
When four lawnmowers are together, the sound level they produce would be around 86 dB. This is due to the way sound levels add up - each additional lawnmower increases the overall sound level by about 3 dB.
wavelength
The compression of a longitudinal wave is measured by the measure of how close the particles in the medium are to each other when the wave is at its peak compression point. This can be quantified by measuring the density or pressure of the medium at that point.
The sound level in decibels (dB) required for a 1 sone loudness at a frequency of 50 Hz would be around 40 dB. This is because 1 sone is approximately equal to 40 phons, and for a 50 Hz tone, 40 phons is equivalent to around 40 dB SPL (Sound Pressure Level).
Devices, such as amplifiers can't be linear over all input values. At some point they just can't output the required output power. I.e. an amplifier that increases input power by a factor of 10, may not be able to amplify a signal that comes in that is, let's say 10 watts. The point where the device is outputing 1 dB less POWER (which is roughly running at 80%) than it should is the 1 dB compression point. So lets say a 10 watt signal is input, and that the signal should be amplified by a factor of 10, and should output 100 watts. Let's also say the system output power is actually 1 dB down from the expected value and outputting roughly 80 watts, 10 watts is the input 1 dB compression point. Also, look here: http://www.rfcafe.com/references/electrical/p1db.htm
db
yes it = 1
A signal starts at point X. As it travels to point Y, it loses 10db. At point Y, the signal is boosted by 5db. As the signal travels to point Z, it loses 7db. What is the db strength of the signal at point Z?
Yes, if #1 is at TDC on the compression stroke.
An ischemic compression is a static compression applied by the therapist's thumbs, fingertips, or olecranon to a trigger point.
In power wattage increases by two times for every three DBs of increase. A starting point is needed to do this calculation. The equation you're looking for is 10*log |P| = P in dB for example, 0 dB = 1 watt 10 dB = 10 watts for 13.936dB, 10^1.3936 = 24.75 watts.
You must find a resistance value for 0 dB as reference. If 1 Ohm = 0 dB then 10 ohms = 20 dB and 100 ohms = 40 dB.
The sound of Mach 1 is around 130 dB.
When four lawnmowers are together, the sound level they produce would be around 86 dB. This is due to the way sound levels add up - each additional lawnmower increases the overall sound level by about 3 dB.
"3 dB" is a nickname for "1/2 power". "1/2 power" in dB = 10 log(1/2) = 10 (-0.30103) = -3.01 dB
wavelength