The efficiency of the car's engine can be calculated using the formula: Efficiency = (Useful energy output / Total energy input) x 100%. In this case, the useful energy output is the heat input minus the waste heat: 400000 J - 300000 J = 100000 J. Therefore, the efficiency would be (100000 J / 400000 J) x 100% = 25%.
The efficiency of the car's engine is calculated as the ratio of the useful work output to the total heat input. In this case, the useful work output is 500000 joules (2000000 J - 1500000 J) and the total heat input is 2000000 joules. Therefore, the efficiency is 500000 joules / 2000000 joules, which equals 0.25 or 25%.
The efficiency of the car's engine is calculated by dividing the useful energy output by the energy input. In this case, the useful energy output would be 5000 joules (20000 input - 15000 waste heat), thus the efficiency would be 5000/20000 = 0.25 or 25%.
The efficiency of the car's engine can be calculated using the formula: Efficiency = (Useful energy output / Total energy input) * 100%. In this case, the useful energy output is the heat used for work, which is (2000000 - 150000) Joules. Therefore, the efficiency would be ((2000000 - 150000) / 2000000) * 100% = 92.5%.
To convert joules to kilojoules, divide the number of joules by 1000. For example, 1 kilojoule = 1000 joules, 5000 joules = 5 kilojoules.
A calorie is about 4.2 joules, therefore a kilocalorie is about 4200 joules. You can multiply by this number.
on a sankey diagram it show that energy in divided by useful energy out to get efficientcy so if heat is lost then more joules is let out which means less effientcy
The efficiency of the car's engine is calculated as the ratio of the useful work output to the total heat input. In this case, the useful work output is 500000 joules (2000000 J - 1500000 J) and the total heat input is 2000000 joules. Therefore, the efficiency is 500000 joules / 2000000 joules, which equals 0.25 or 25%.
25%
25 percent
25 percent
60,000 joules per 10 seconds = 6,000 joules per second = 6,000 watts
The efficiency of the car's engine is calculated by dividing the useful energy output by the energy input. In this case, the useful energy output would be 5000 joules (20000 input - 15000 waste heat), thus the efficiency would be 5000/20000 = 0.25 or 25%.
kinetic energy is 1/2mv^2, our velocity is 20 m/s , our mass is 2000 kg. Plugging it in you get 1/2 (2000) (400) = 1000 * 400 = 400000 joules
400
25%Take Input - Waste = Differencethen D / I = Effeciencyso, 400000 - 300000 = 100000and 100000 / 400000 = .25 or 25%now ask the teacher next time...Dont answer the question if you are going to get an attitude...
The efficiency of the car's engine can be calculated using the formula: Efficiency = (Useful energy output / Total energy input) * 100%. In this case, the useful energy output is the heat used for work, which is (2000000 - 150000) Joules. Therefore, the efficiency would be ((2000000 - 150000) / 2000000) * 100% = 92.5%.
There are 56,000 joules in 56 kilojoules. This is because there are 1,000 joules in a kilojoule.