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The efficiency of the car's engine can be calculated using the formula: Efficiency = (Useful energy output / Total energy input) x 100%. In this case, the useful energy output is the heat input minus the waste heat: 400000 J - 300000 J = 100000 J. Therefore, the efficiency would be (100000 J / 400000 J) x 100% = 25%.

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What is the effciency of a car's engine when heat input is 2000000 joules and the waste heat is 1500000 joules?

The efficiency of the car's engine is calculated as the ratio of the useful work output to the total heat input. In this case, the useful work output is 500000 joules (2000000 J - 1500000 J) and the total heat input is 2000000 joules. Therefore, the efficiency is 500000 joules / 2000000 joules, which equals 0.25 or 25%.


What is the efficiency of a car's engine when he input is 20000 joules and the waste heat is 15000 joules?

The efficiency of the car's engine is calculated by dividing the useful energy output by the energy input. In this case, the useful energy output would be 5000 joules (20000 input - 15000 waste heat), thus the efficiency would be 5000/20000 = 0.25 or 25%.


What is the efficiency of a cars engine when heat input 2000000 joules and waste heat is 150000 joules?

The efficiency of the car's engine can be calculated using the formula: Efficiency = (Useful energy output / Total energy input) * 100%. In this case, the useful energy output is the heat used for work, which is (2000000 - 150000) Joules. Therefore, the efficiency would be ((2000000 - 150000) / 2000000) * 100% = 92.5%.


What is the correct conversion between joules and kilojules?

To convert joules to kilojoules, divide the number of joules by 1000. For example, 1 kilojoule = 1000 joules, 5000 joules = 5 kilojoules.


How many joules are in 55.2 calories?

A calorie is about 4.2 joules, therefore a kilocalorie is about 4200 joules. You can multiply by this number.

Related Questions

How heat loss reduces effiency of a device?

on a sankey diagram it show that energy in divided by useful energy out to get efficientcy so if heat is lost then more joules is let out which means less effientcy


What is the effciency of a car's engine when heat input is 2000000 joules and the waste heat is 1500000 joules?

The efficiency of the car's engine is calculated as the ratio of the useful work output to the total heat input. In this case, the useful work output is 500000 joules (2000000 J - 1500000 J) and the total heat input is 2000000 joules. Therefore, the efficiency is 500000 joules / 2000000 joules, which equals 0.25 or 25%.


What is the efficiency of a car's engine when the heat input is 100000 joules and the waste heat is 75000 joules?

25%


What is the efficiency of lawn mower's engine when the heat input is 1000 joules and the waste heat is 750 joules?

25 percent


What is efficiency of lawn mower's engine when the heat input is 1000 joules and the waste heat is 750 joules?

25 percent


What is the power output of an engine that does 60 000 joules of work in 10 seconds?

60,000 joules per 10 seconds = 6,000 joules per second = 6,000 watts


What is the efficiency of a car's engine when he input is 20000 joules and the waste heat is 15000 joules?

The efficiency of the car's engine is calculated by dividing the useful energy output by the energy input. In this case, the useful energy output would be 5000 joules (20000 input - 15000 waste heat), thus the efficiency would be 5000/20000 = 0.25 or 25%.


What is kinetic energy of a 2000-kg car moving at 20 ms?

kinetic energy is 1/2mv^2, our velocity is 20 m/s , our mass is 2000 kg. Plugging it in you get 1/2 (2000) (400) = 1000 * 400 = 400000 joules


If an engine must do 500 joules of work to pull a 100 newtons load up to a height of 4 meters What is the efficiency of the engine?

400


What is the efficiency of a cars engine when heat input is 2000000 joules and the waste heat is 1500000 joules?

25%Take Input - Waste = Differencethen D / I = Effeciencyso, 400000 - 300000 = 100000and 100000 / 400000 = .25 or 25%now ask the teacher next time...Dont answer the question if you are going to get an attitude...


What is the efficiency of a cars engine when heat input 2000000 joules and waste heat is 150000 joules?

The efficiency of the car's engine can be calculated using the formula: Efficiency = (Useful energy output / Total energy input) * 100%. In this case, the useful energy output is the heat used for work, which is (2000000 - 150000) Joules. Therefore, the efficiency would be ((2000000 - 150000) / 2000000) * 100% = 92.5%.


How many joules are in 56 kilo joules?

There are 56,000 joules in 56 kilojoules. This is because there are 1,000 joules in a kilojoule.

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