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Which describes a trains acceleration if it changes speed from 25ms to 10ms in 240s?
The acceleration of the train can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. Plugging in the values: (10 m/s - 25 m/s) / 240 s = -0.0625 m/s^2. The negative sign indicates that the train is decelerating.
A car moving at 10ms is accelerated at a rate of 5ms2 over a 4 second period What would the speed be after 3 seconds?
I presume that you mean 'An object travelling initally at 10m/s, accelerates at 4m/s2 for 8s; what is its final speed? If it is accelerating at 4 m/s2, it gains 4m/s every s v= u + at where v is the final speed, u is the initial speed, a is the acceleration and t is the time v = 10 + 4(8)= 42 m/s
Mass is 145g and velocity is 25ms Find the answer using kinetic energy formula?
Kinetic energy is 0.45 joules using the formula Ek = ½ x mv2
What is the mass of a baseball thrown at 25ms resulting in a momentum of 10kgms?
Just use the definition of momentum, as mass x velocity. In this case, you need to divide the momentum by the velocity, to get the mass.
A stone projected horizontally from the top of a vertical wall with a velocity of 25ms hits the horizontal ground at a point 60m from the base of wall calculate the time of flight of the stone g10ms?
The time of flight can be calculated using the equation ( time = \frac{2 \times distance}{velocity} ). In this case, the distance is 60m and the velocity is 25m/s. Plugging in the values, we get ( time = \frac{2 \times 60}{25} = 4.8 ) seconds.
When mass is 5 kg and accelaration is 25ms-2 what will be the force?
When Using Newtons Laws you get: F=m*a=5 kg*25 m/s2=125 N
Which glass pitbull using eye glass in international love?
I think it's prada 25ms
Which describes a trains acceleration if it changes speed from 25ms to 10ms in 240s?
The acceleration of the train can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. Plugging in the values: (10 m/s - 25 m/s) / 240 s = -0.0625 m/s^2. The negative sign indicates that the train is decelerating.
A car moving at 10ms is accelerated at a rate of 5ms2 over a 4 second period What would the speed be after 3 seconds?
I presume that you mean 'An object travelling initally at 10m/s, accelerates at 4m/s2 for 8s; what is its final speed? If it is accelerating at 4 m/s2, it gains 4m/s every s v= u + at where v is the final speed, u is the initial speed, a is the acceleration and t is the time v = 10 + 4(8)= 42 m/s
How do you calculate mean latency?
To find the mean of anything, including latency, add all the values together and divide the result of that by the total number of input values. So, say you had this: 24ms 57ms 25ms 45ms The total of these numbers is 151 There were 4 values when we started so we divide our total by 4 151/4 = 37.75 So our mean latency is 37.75ms Hope this helps!
Mass is 145g and velocity is 25ms Find the answer using kinetic energy formula?
Kinetic energy is 0.45 joules using the formula Ek = ½ x mv2
What is the mass of a baseball thrown at 25ms resulting in a momentum of 10kgms?
Just use the definition of momentum, as mass x velocity. In this case, you need to divide the momentum by the velocity, to get the mass.
A stone projected horizontally from the top of a vertical wall with a velocity of 25ms hits the horizontal ground at a point 60m from the base of wall calculate the time of flight of the stone g10ms?
The time of flight can be calculated using the equation ( time = \frac{2 \times distance}{velocity} ). In this case, the distance is 60m and the velocity is 25m/s. Plugging in the values, we get ( time = \frac{2 \times 60}{25} = 4.8 ) seconds.
How many milliseconds after the zero crossing of the AC voltage reaches of 1kHz and 10kHz for the first time its maximum value?
1khz you get 2000 zero crossings per sec or .5 ms between zeros depending on which zero crossing you pick it may be .25ms or .75ms to the max or min for ten khz .05ms between zeros .025ms or .075ms
What is ip address of a website?
A website name is resolved to the IP address by a DNS (Domain Name Server) allowing websites to be navigated to via their familiar domain name (such as "Google.com") rather than to a hard-to-remember IP address. IP addresses used by networks and the World-Wide Web to uniquely identify a domain (such as a computer or website). Websites are identified uniquely using an IP address, although physically there may be several servers handling the website. To find out the IP address of a website, open a command prompt and type "ping <website URL>"- the IP address of the website will be resolved and displayed for the given domain. Here is an example: C:\>ping google.com Pinging google.com [74.125.91.106] with 32 bytes of data: Reply from 74.125.91.106: bytes=32 time=27ms TTL=49 Reply from 74.125.91.106: bytes=32 time=27ms TTL=49 Reply from 74.125.91.106: bytes=32 time=25ms TTL=49 Reply from 74.125.91.106: bytes=32 time=29ms TTL=49 Ping statistics for 74.125.91.106: Packets: Sent = 4, Received = 4, Lost = 0 (0% loss), Approximate round trip times in milli-seconds: Minimum = 25ms, Maximum = 29ms, Average = 27ms The IP address in this example (for google.com) is 74.125.91.106
A stone is allowed to fall from the top of a tower 100m high and at the same time other stone is projected vertically upwards with a velocity of 25ms Calculate when and where the two stones will meet?
The altitude of the first stone above the ground is [ H = 100 - 1/2 G T2 ].The altitude of the second stone is [ H = 25T - 1/2 G T2 ].The stones meet when their altitudes are the same.100 + 1/2 G T2 = 25T - 1/2 G T2Add 1/2 G T2 to each side of the equation:25 T + GT^2 -100 = 0They meet when T = 2.15 seconds after the drop-and-tossPlug that into the expression for the position of the dropped stone:100 - 1/2 G T2 = 100 - (4.9) (16) = 100 - 78.4 = 21.6 meters from the ground.
A stone is dropped from the top of a tower 100m in height and at the same time another stone is projected vertically upwards from the ground with a velocity of 25ms find where and when the two stone?
The position of an object in a gravity field is given by: S = 1/2 * a *t ^2 + v * t + x So making the assumption that both are subject to Earth's gravity, a = - 9.81 m/s^2 (negative acting down). Assuming the top stone starts at rest, V_top = 0 m/s, V_bottom = 25 m/s. Taking the problem statement, x_top = 100 m and x_bottom = 0 m. If you want the time when they impact one another, set the two position equations equal and solve for t: 1/2* - 9.81 * t ^2 + 0 + 100 = 1/2 * -9.81 * t^2 + 25 * t + 0 So the acceleration terms cancel, and t = 4 seconds. To check, solve both position equations at t = 4 s. S = 1/2 * -9.81 * 4 ^2 + 0 + 100 = 21.52 m S = 1/2 * -9.81 * 4 ^ 2 + 25 * 4 + 0 = 21.52 m So there you go. The time is 4 seconds, the position is 21.52 m above the ground.
