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What is the efficiency of a car's engine when he input is 20000 joules and the waste heat is 15000 joules?
The efficiency of the car's engine is calculated by dividing the useful energy output by the energy input. In this case, the useful energy output would be 5000 joules (20000 input - 15000 waste heat), thus the efficiency would be 5000/20000 = 0.25 or 25%.
What is the efficiency of a cars engine when heat input 2000000 joules and waste heat is 150000 joules?
The efficiency of the car's engine can be calculated using the formula: Efficiency = (Useful energy output / Total energy input) * 100%. In this case, the useful energy output is the heat used for work, which is (2000000 - 150000) Joules. Therefore, the efficiency would be ((2000000 - 150000) / 2000000) * 100% = 92.5%.
What is the efficiency of a street cleaners engine when is that heat input is 200000 Joules and the waste he is 150000 Joules?
The efficiency of the street cleaner's engine is calculated by dividing the useful output (work done) by the input energy. In this case, the useful output is 150000J (work done) and the input energy is 200000J. The efficiency would be 150000J / 200000J = 0.75 or 75%.
How Efficiency is measured in joules?
Efficiency is typically measured as the ratio of useful energy output to the total energy input, expressed as a percentage. In terms of joules, the efficiency can be calculated as the useful energy output in joules divided by the total energy input in joules, multiplied by 100. This calculation helps assess how effectively a system converts energy input into useful output.
What is the effciency of a car's engine when heat input is 2000000 joules and the waste heat is 1500000 joules?
The efficiency of the car's engine is calculated as the ratio of the useful work output to the total heat input. In this case, the useful work output is 500000 joules (2000000 J - 1500000 J) and the total heat input is 2000000 joules. Therefore, the efficiency is 500000 joules / 2000000 joules, which equals 0.25 or 25%.
What is the efficiency of a car's engine when he input is 20000 joules and the waste heat is 15000 joules?
The efficiency of the car's engine is calculated by dividing the useful energy output by the energy input. In this case, the useful energy output would be 5000 joules (20000 input - 15000 waste heat), thus the efficiency would be 5000/20000 = 0.25 or 25%.
What is the efficiency of a cars engine when heat input 2000000 joules and waste heat is 150000 joules?
The efficiency of the car's engine can be calculated using the formula: Efficiency = (Useful energy output / Total energy input) * 100%. In this case, the useful energy output is the heat used for work, which is (2000000 - 150000) Joules. Therefore, the efficiency would be ((2000000 - 150000) / 2000000) * 100% = 92.5%.
What is the efficiency of a street cleaners engine when is that heat input is 200000 Joules and the waste he is 150000 Joules?
The efficiency of the street cleaner's engine is calculated by dividing the useful output (work done) by the input energy. In this case, the useful output is 150000J (work done) and the input energy is 200000J. The efficiency would be 150000J / 200000J = 0.75 or 75%.
How Efficiency is measured in joules?
Efficiency is typically measured as the ratio of useful energy output to the total energy input, expressed as a percentage. In terms of joules, the efficiency can be calculated as the useful energy output in joules divided by the total energy input in joules, multiplied by 100. This calculation helps assess how effectively a system converts energy input into useful output.
What is the effciency of a car's engine when heat input is 2000000 joules and the waste heat is 1500000 joules?
The efficiency of the car's engine is calculated as the ratio of the useful work output to the total heat input. In this case, the useful work output is 500000 joules (2000000 J - 1500000 J) and the total heat input is 2000000 joules. Therefore, the efficiency is 500000 joules / 2000000 joules, which equals 0.25 or 25%.
What is the effiency of a cars engine when heat input is 400000 joules and the waste heat is 300000 joules?
The efficiency of the car's engine can be calculated using the formula: Efficiency = (Useful energy output / Total energy input) x 100%. In this case, the useful energy output is the heat input minus the waste heat: 400000 J - 300000 J = 100000 J. Therefore, the efficiency would be (100000 J / 400000 J) x 100% = 25%.
Is it reasonable to have a work output of 150 Joules when work input is 110 Joules?
No. It is not reasonable. If that ever happened, we would have to ask where the additional 40 joules came from, since energy cannot be created or destroyed. If there were something inside the box that added 40 joules to the 110 passing through, then that 40 would need to be added to the "input" work.
What is the efficiency of a car's engine when the heat input is 100000 joules and the waste heat is 75000 joules?
25%
What is efficiency of lawn mower's engine when the heat input is 1000 joules and the waste heat is 750 joules?
25 percent
What is the efficiency of lawn mower's engine when the heat input is 1000 joules and the waste heat is 750 joules?
25 percent
What is the efficiency of a street cleaner's engine when the heat input is 200000 joules and the heat waste is 150000 joules?
25 percent
What is the efficiency of a street cleaners engine when the heat input is 200000 joules and the waste is 150000 joules?
If the waste heat is 15 compared to the total heat input of 20 (ignoring the thousands) this means the heat doing useful work is 5, which represents 25 percent of the total input heat, so this is the efficiency. Waste heat in a car is the sum of the engine cooling losses and the exhaust losses, the rest is converted to mechanical energy which is useful. 25%
