0
What else can I help you with?
What is the density of an object with a mass of 2g that when placed in a graduated cylinder with water raises the volume of water from 20ml to 30 ml?
The volume of the object is the difference in water level before and after the object is added, which is 10 ml (30 ml - 20 ml). The density of the object is mass divided by volume, so 2g / 10 ml = 0.2 g/ml. Therefore, the density of the object is 0.2 g/ml.
How much water would be displaced by 10cm3?
10 cm3 of water would displace an equivalent volume of water when submerged. This displacement would be equal to 10 ml or 10 grams of water.
If a graduated cylinder has a current water level of 30 ml and you add an object which causes the water level to rise 53 ml what is the volume of the object you placed in the water?
The volume of the object placed in the water is 23 ml. This can be calculated by subtracting the initial water level (30 ml) from the final water level (53 ml).
Object displaces 16.5 mL of water what is the volume?
"Displacement" means pushing the water away from space where the object wants to be. If 16.5 mL of water is displaced, then the volume of the object must be 16.5 mL. At least the volume of the part of it that's down in the water, like if it's floating.
An object displaces 652 ml of water. The volume of the object is?
652 cc (unless it was floating).
If you have 10ml of water and it weighs 13.6 grams what is the exact volume?
10 ml of water has 10 c.c. volume
10 ml is equal to how many teaspoon?
10 mm can not equal any volume measurement. Mm is length.
What is the volume of water in a 500 ml bottle of rubbing alcohol that has a concentration of 70 percent by volume?
There is 500 ml of liquid and 70% of it is alcohol so 30% is water. .3x500 =150 so 150 ml of H2 O Note 30% = .3=3/10 and 3/10 x500=1500/10=150
What is the density of an object with a mass of 2g that when placed in a graduated cylinder with water raises the volume of water from 20ml to 30 ml?
The volume of the object is the difference in water level before and after the object is added, which is 10 ml (30 ml - 20 ml). The density of the object is mass divided by volume, so 2g / 10 ml = 0.2 g/ml. Therefore, the density of the object is 0.2 g/ml.
What is the volume of water if the mass is 118 mL?
The volume of water is 118 mL, since the mass and volume of water are equivalent at room temperature.
What is 1 volume of water?
1 Volume of water is nothing but volume of water measured in liters or ml EG Volume = mass/density 1 Volume= 1 gm/1 gm/cc = 1 cc therefore 10 volume = 10 cc if it is in KG, 10 volume= 10 kg/10kg/L = 10 L
How many mgs in 10 gms?
10 cubic centimeters (cc) equals 10 milliliters (ml) or the volume equivalent to 10 grams of pure water.
What is the percentage of volume?
Volume percent (v/v %) is defined as: volume percent = [(volume of solute) / (volume of solution)] x 100% Volume percent is handy when preparing solutions of liquids. Concentration of a solution can be stated in volume percentages. Be aware that volume of solution is in formula denominator, not volume of solvent. Thus to get 10% v/v solution of ethanol in water you can take 10 ml of ethanol and add enough water to have total 100 ml of resulting solution. It is worth to mention volumes of solute and solvent cannot be simply added to get volume of solution. For instance if you add 10 ml of ethanol to 90 ml of water the volume of the solution will be less than 100 ml.
Can you make 10 volume developer out of 20?
To make 10 volume developer from 20 volume developer, you can mix equal parts of 20 volume developer and distilled water. For example, mix 1 part of 20 volume developer with 1 part distilled water to create 10 volume developer.
A volume of 10 cubic centimeters is equal to how many mL?
10 mL
What is the volume of 6.5 g of water?
Since the density (mass divided by volume) of water is about 1.0 g/mL the volume of 6.5 gram is6.5(g) / 1.0(g/mL) = 6.5 mL
How many mL of water are present in 250 mL of a 15 percent by volume aqueous hydrochloric acid solution?
The water volume is 212,5 mL.
