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What would be the final temperature when 100 grams of water at 30 degrees c is mixed with 50 grams of water at 60 degree c?
The key to solving this problem is that the heat lost by the warmer water is equal to the heat gained by the colder water. Knowing the relation Q = mc(change in T), this problem can be solved with algebra. Q is heat, m is mass in grams, c is the specific heat of water 4.184 J/ g C, and T is temperature. 100g * 4.184 J / g C * (x - 30 C) = 50 g * 4.184 J / g C * (60 C - x). The final answer should have x = to 40 degrees C.
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What is the final temperature of the mixture if 100gram of water at 70temperature is added to 200gram of cold water at 10temperature and well stirred?
I'll assume here that by "70 temperature" you mean "70 degrees Celsius". Basically, you have to calculate the average temperature of all of the water in the mixture, which will be the final temperature once it's well stirred. The 200 grams of water at 10 degrees represent 2/3 of the total amount of water (300 grams), so thus, multiply 10 by 2/3 to determine their contribution to the final temperature. You will get 20/3. The 100 grams of water at 70 degrees represent 1/3 of the total amount of water, so multiply 70 by 1/3 to determine their contribution to the final temperature. You will get 70/3. When you add together the two temperatures you get 90/3, which is equal to 30. Therefore, the final temperature is 30 degrees Celsius.
What is the final temperature of 25.0 grams of water at 22.0 degrees Celsius after it absorbs 459 joules of heat?
To calculate the final temperature, you need to use the formula: q = mcΔT, where q is the heat energy, m is the mass, c is the specific heat capacity of water, and ΔT is the change in temperature. Rearrange the formula to solve for the final temperature Tf: Tf = (q / (m*c)) + Ti, where Ti is the initial temperature. Plug in the values and calculate the final temperature.
In the space below show a numerical setup for calculating the total amount of heat required to raise the temperature of the H2O(l) from 0 degrees C to its final temperature?
Q = m * c * ΔT Where: Q = total heat required m = mass of water (in grams) c = specific heat capacity of water (4.18 J/g°C) ΔT = change in temperature (final temperature - initial temperature)
One hundred twenty grams of metal at 88 degree Celsius is poured into a 70 grams insulated cup contains 250 grams of water at 16 degree Celsius.The final temperature of the mixture is 17.5 degree celc?
To solve this problem, you can use the principle of conservation of energy: Heat gained by the metal = heat lost by the metal + heat gained by the water Plug in the given values and use the specific heat capacity of metal and water to calculate the initial temperature of the metal before mixing.
Is Temperature the flow of energy from warm matter to cool matter?
No, certainly not.Temperature is a measure of the average kinetic energy of the particles in a body. The temperature of a thing is how strongly the little bits of that thing are shaking about. If they shake hard enough, meaning that the thing is hot enough, they shake the bits apart, so that the thing melts or evaporates.If I take something hot and put it against something cold, then the shaking of the molecules of the hot matter jostle the molecules of the cold matter, passing on some of their energy. To us that is a flow of heat energy from the hot matter to the cold.Get that straight! It is a flow of energy, not of temperature, and the temperature is not the flow!But, you say, suppose I take 10 grams of water at 95 degrees and put them against 10 grams of water at 35 degrees, I will get 20 grams at 65 degrees, right? How does that differ from a flow of temperature?Temperature does not flow; heat does. I chose that example carefully to make it look like a flow of temperature. Think of a different example: suppose that we put 10 grams of mercury at 95 degrees against 10 grams of water at 35 degrees; then we would get the whole lot at just about 37 degrees instead of 65 degrees, because it takes about 30 times as much heat to increase the temperature of one gram of water by one degree as it takes to heat one gram of mercury by one degree.Now, what happened to that "flow of temperature"?Get the picture?Heat will flow until the temperatures are the same all right, but the heat still is the only thing that flows.But, you say, isn't the temperature itself the flow?No, because if I have water at 95 degrees and I don't have it touching anything at a different temperature, then there is no flow of heat (or energy, if you like; same thing in our examples) and yet the temperature stays at 95. If the temperature were the flow, then zero flow would mean zero temperature, right? And do we get zero temperature? Not a bit of it; we get 95 degrees!Is this helping you get it straight? If not, ask again.
What is the final temperature when 625 grams of water at 75 degrees loses 7.96?
The final temperature is 59.9°C.
What would be the final temperature when 250 grams of water at 100 degrees celsius is mixed with 525 grams of water at 30 degrees celsius?
The final temperature would be approximately 54.2 degrees Celsius. This can be calculated using the principle of conservation of energy, where the heat lost by the hot water is equal to the heat gained by the cold water.
If 1200 calories of heat is added to 40 grams of water at 20 degree what will be the final temperature?
I believe it will be 145.52 degrees Celsius if I did my math correctly. You need to convert calories to joules. I believe one joule raises the temp of 1 gram water by 1 degree Celsius so 1200*4.184=5020.8 J /40grams=125.52 temp increase+20=145.52 degrees Celsius.
What is the final temperature of the mixture if 100gram of water at 70temperature is added to 200gram of cold water at 10temperature and well stirred?
I'll assume here that by "70 temperature" you mean "70 degrees Celsius". Basically, you have to calculate the average temperature of all of the water in the mixture, which will be the final temperature once it's well stirred. The 200 grams of water at 10 degrees represent 2/3 of the total amount of water (300 grams), so thus, multiply 10 by 2/3 to determine their contribution to the final temperature. You will get 20/3. The 100 grams of water at 70 degrees represent 1/3 of the total amount of water, so multiply 70 by 1/3 to determine their contribution to the final temperature. You will get 70/3. When you add together the two temperatures you get 90/3, which is equal to 30. Therefore, the final temperature is 30 degrees Celsius.
What is the final temperature of 25.0 grams of water at 22.0 degrees Celsius after it absorbs 459 joules of heat?
To calculate the final temperature, you need to use the formula: q = mcΔT, where q is the heat energy, m is the mass, c is the specific heat capacity of water, and ΔT is the change in temperature. Rearrange the formula to solve for the final temperature Tf: Tf = (q / (m*c)) + Ti, where Ti is the initial temperature. Plug in the values and calculate the final temperature.
How many calories of heat would it take to raise the temperature of 256 grams of water from 20 degrees to 99 degrees?
A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.
What is the density of nitrobenzene at temperature of 100 degrees Fahrenheit?
74.009 pounds per cubic foot is the density of nitrobenzene at 100 degree Fahrenheit.
What is the final equilibrium temperature when 15 grams of milk at 22 degrees Celsius is added to 185 grams of coffee at 86 degrees Celsius?
The final equilibrium temperature can be found using the principle of conservation of energy. The heat lost by the coffee as it cools down is equal to the heat gained by the milk as it warms up. Using the formula Q = mcΔT, where Q is the heat transferred, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature, you can calculate the final temperature.
Is gram used to measure the temperature in the metric system?
No, grams are unit of mass, not temperature. Temperature is measured in °C (degrees celsius) or for scientific work in 'K' K = °C + 273.15
If 50 grams of a substance with a temp of 20 degree Celsius and specific heat of 2 is mixed with 200 grams of water with a temperature of 40 degree Celsius what will be the equilibrium temperature of?
Heat gained by one object has to equal the heat lost by the other object. The final temperature of the two objects will be the same.Object 1:mass1 = 50 ginitial T1 = 20 oCCg = 2 J/degree/gramfinal T1 = TfChange in temperature = Tf - T1Q = Cg x change in T x mass= 2 x ( Tf - T1 ) x 50Water:Mass = 200 gCg = 4.18 J/ degree/ gramChange in T = Tf - 40Q = 4.18 x (Tf - 40) x 2004.18 x (Tf - 40) x 200 = -(2 x ( Tf - 20 ) x 50)Tf = 37.9 oC
In the space below show a numerical setup for calculating the total amount of heat required to raise the temperature of the H2O(l) from 0 degrees C to its final temperature?
Q = m * c * ΔT Where: Q = total heat required m = mass of water (in grams) c = specific heat capacity of water (4.18 J/g°C) ΔT = change in temperature (final temperature - initial temperature)
How many grams of the solid solute will dissolve in 100 grams of water at C?
The amount of solute that will dissolve in water at a specific temperature depends on the solubility of the solute at that temperature. You need to check the solubility of the specific solute at the specified temperature (in degrees Celsius) to determine how many grams will dissolve in 100 grams of water.
