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What would be the resistance of a 12 volt light bulb with 55 amps flowing through it?
In theory the formula V = IR (I is current), 12/55 or approximately 0.2 ohms. But in reality the resistance probably will go to infinity, as that much current would almost certainly blow the filament. I doubt any 12 V bulb could dissipate 12*55 = 660 watts for any extended amount of time. But who knows...
What else can I help you with?
What current flows through a hair dryer plugged into a 120 volt circuit if it has a resistance of 25 ohms?
The current flowing through the hair dryer would be 4.8 amps (120 V / 25 Ω = 4.8 A).
What would a light bulb act as in a circuit?
A light bulb would act as a load in a circuit. It transforms electrical energy into light energy and heat when current passes through it. It offers resistance to the flow of current, causing it to light up.
What is the current when a 12 volt battery is connected through a resistance of 25 ohms?
The current flowing through the circuit can be calculated using Ohm's Law: I = V/R, where I is the current, V is the voltage (12 volts), and R is the resistance (25 ohms). Plugging in the values, the current would be 0.48 amperes.
Compare the current in a 2 light bulbs wired in a series circuit?
In a series circuit, the current passing through each component, like the light bulbs, is the same. This means that both light bulbs would have the same current flowing through them. If one light bulb were to burn out, current flow through both bulbs would stop.
What would induce a greater electric current in a wire?
A greater electric current in a wire can be induced by increasing the voltage applied across the wire or decreasing the resistance of the wire. Both factors contribute to Ohm's Law (V=IR), where V is voltage, I is current, and R is resistance. Increasing the voltage or decreasing the resistance will lead to a higher current flowing through the wire.
Would it be true to say that current causes voltage?
Volts = Current x Resistance. The voltage is where the potential resides for the amount of current flowing through a resistance. Think about the voltage as a potential source of electrons that then flow through a circuit depending on the Load, or resistance in this example.
Will a light bulb evaporate water?
If you were to put a bare wire belonging to anything in a glass of water, the electricity flowing through the wire would have no reason to continue to travel through the wire instead of dispersing in the water. The water offers less resistance, so the electricity flows through that instead of the wire. This is known as creating a short circuit, or a short, for short! With no electricity flowing through the bulb, it will turn off.
What current flows through a hair dryer plugged into a 120 volt circuit if it has a resistance of 25 ohms?
The current flowing through the hair dryer would be 4.8 amps (120 V / 25 Ω = 4.8 A).
How much current flows in a 75-walt's light-bulb connected to a 110 voltage wall outlet?
The current flowing through the 75-watt light bulb connected to a 110-volt wall outlet can be calculated by using the formula: Power = Voltage x Current. Therefore, the current flowing through the light bulb would be approximately 0.68 amps.
If more electrons were flowing through a wire what would be increased?
If more electrons were flowing through a wire, the thing that would be increased would be the current. This is the flow of the carriers of electrical charges.
What would a light bulb act as in a circuit?
A light bulb would act as a load in a circuit. It transforms electrical energy into light energy and heat when current passes through it. It offers resistance to the flow of current, causing it to light up.
What is the current when a 12 volt battery is connected through a resistance of 25 ohms?
The current flowing through the circuit can be calculated using Ohm's Law: I = V/R, where I is the current, V is the voltage (12 volts), and R is the resistance (25 ohms). Plugging in the values, the current would be 0.48 amperes.
What happens if you take away a load from a series circuit?
As an example imagine a 60 W light bulb running off 120 V. The current will be 1/2 A. Now assume that you put a second 60 W bulb in series with the first. Now the resistance of the single 60 W bulb is 240 Ohms. The 1/2 A flowing through the bulb heats up the filament wire and causes an amount of light to be emitted. Resistance in series adds, so the total resistance for two of the bulbs in series is 480 Ohms and by Ohms law V = I x R, the current through each bulb will be 1/4 amp and hence the bulbs will be less bright.
An electric lamp has a resistance of 534 ohms when connected to a 230v supply the current flowing would be?
I = E/R
Do light bulbs use more energy over time?
An incandescent light bulb is essentially a wire through which current flows. The wire gets heated up and glows giving off light. According to Ohm's Law Volts = Current x Resistance. In this case resistance is the resistance of the filament. Since in a residence the voltage remains more or less constant, the way more energy would be use is if more current passed through the filament. If the resistance of the filament decreased then the current would increase. Not sure how an aging bulb would have a decreased resistance. If this were somehow possible such that the composition of the filament changes and reduced resistance then the energy required to operate the bulb would increase.
Compare the current in a 2 light bulbs wired in a series circuit?
In a series circuit, the current passing through each component, like the light bulbs, is the same. This means that both light bulbs would have the same current flowing through them. If one light bulb were to burn out, current flow through both bulbs would stop.
How any volts are produced in a circuit with 40 amp's of current flowing through a wire with 5 ohms of resistance?
It is a voltage (potential) applied to a load that causes a current to flow through the load. Ohm's Law encapsulates this principal and states Volts = Current x Resistance. In your example, the applied voltage would be 200 volts.
