As heat is a form of energy, it isn't lost or gained, it's just converted into another form of energy.
it depends on which side of the pendulum you are in. when water is in its liquid state, then heat is lost. if water is in its solid state, then heat is gained.
Heat is lost.
water loses heat when it is at 0'
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If no heat is exchanged with other substances, yes.
it depends on conversion. wind to wind energy. Sun to solar Energy. and water to hydro have no loss only gained but on other hand electric to heat energy like also some heat will be lost. in nuclear energy some energy also lost during conversion.
-heat capacity of the object (equal to mass times the specific heat capacity of the object) -overall change in temperature.
Vaporization is an endothermic process. It takes energy to heat up material to the point that it vaporizes, so energy is gained by the material being vaporized and lost by the environment.
Heat is lost to or gained from the air while falling.
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It goes to the environment.
In Tropical countries when the water in the water bodies freezes, itgives out its heat to the surrounding. The water in the water bodies first forms a thin layer of ice on top as it freezes. This further reduces heat lost, since the ice layer does not allow heat to escape.Therfore,both phenomenons ,of giving out heat and prevention of heat escape, help to not let the temperature of the water bodies body fall deep below.This helps in the survival of fishes for a while in colder climates.
Heat lost by the metal = heat gained by the water. Heat gained by the water = 50.0 g x 4.184 J/g K x (28.3-22.2) = 1276 J Heat lost by metal = 1276 J = 34.44 g x Sp Heat x (98.6 - 28.3) Specific Heat = 1276 J / 2421 g K = 0.527 J/g K
If no heat is exchanged with other substances, yes.
Heat gained by one object = Heat lost by the other. Does that help?
it depends on conversion. wind to wind energy. Sun to solar Energy. and water to hydro have no loss only gained but on other hand electric to heat energy like also some heat will be lost. in nuclear energy some energy also lost during conversion.
The energy lost by the hot water will be gained by the cold water until they both come to equal temperature. Then there will no longer be any heat transfer from hot to cold. I think the mathematical relationship is a natural log curve that asymptotically approaches the horizontal - meaning the cooling curve keeps getting less steep over time as the heat is exchanged
Hi, heat transferred = mass x specific heat capacity x rise/fall in temperature If heat is lost then fall in temperature If heat is gained then rise in temperature. More the transfer then greater the difference in temperature.
Hi, heat transferred = mass x specific heat capacity x rise/fall in temperature If heat is lost then fall in temperature If heat is gained then rise in temperature. More the transfer then greater the difference in temperature.
mass times the temperature change rimes specific heat capactiy